# Question 2 million: Now there is a house in Beijing with a price of 10%. Suppose the house price increases by 2 million every year (the price increases by every year), a software

Source: Internet
Author: User

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/* Start the comments in the program header (to avoid any problems encountered during the submission of blog posts, the slash used to indicate that the comments have been deleted)
* Copyright and version Declaration of the program
* File name: txt. c
* Author: liuyongshui
* Question: Now there is a house in Beijing with a price of 2 million. If the house price increases by 10% every year, a software engineer can earn 0.4 million yuan a year.
If he wants to buy this house, no loans, no salary increases, no other income, no food, no consumption every year, then how many years does he need to save enough money to buy this house?
* Problem source:
* Completion date: January 1, April 16, 2013
* Version No.: V1.0
*/

# Include <stdio. h>

Int main ()
{
Int I = 0;
Float salary = 40; // annual salary
Float value = 200; // house price
Float rate = 0.1; // house price increase rate

While (salary * I <value + value * rate * I) // The annual price increases by 2 million.
{
I ++;
}

Printf ("after % d, software engineers can buy a house! \ N ", I );

Return 0;
}

/* Start the comments in the program header (to avoid any problems encountered during the submission of blog posts, the slash used to indicate that the comments have been deleted)
* Copyright and version Declaration of the program
* File name: txt. c
* Author: liuyongshui
* Question: Now there is a house in Beijing with a price of 2 million. If the house price increases by 10% every year, a software engineer can earn 0.4 million yuan a year.
If he wants to buy this house, no loans, no salary increases, no other income, no food, no consumption every year, then how many years does he need to save enough money to buy this house?
* Problem source:
* Completion date: January 1, April 16, 2013
* Version No.: V1.0
*/

# Include <stdio. h>

Int main ()
{
Int I = 0;
Float salary = 40; // annual salary
Float value = 200; // house price
Float rate = 0.1; // house price increase rate

While (salary * I <value + value * rate * I) // The annual price increases by 2 million.
{
I ++;
}

Printf ("after % d, software engineers can buy a house! \ N ", I );

Return 0;
}

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