Question one hundred: Calculate the sum of the Series

Source: Internet
Author: User

[Plain] Description
 
The sequence is defined as follows:
The first item of the series is n, and the subsequent items are the square root of the previous item, and the sum of the first m items of the series is obtained.
 
Input
 
There are multiple groups of input data. Each group occupies one row and consists of two integers n (n <10000) and m (m <1000). The meanings of n and m are as described above.
 
Output
 
For each group of input data, the sum of the output columns, each test instance occupies a row, requires that the precision be kept with 2 decimal places.
 
Sample Input
 
 
81 4
2 2
 
Sample Output
 
 
94.73
3.41

Description

The sequence is defined as follows:
The first item of the series is n, and the subsequent items are the square root of the previous item, and the sum of the first m items of the series is obtained.

Input

There are multiple groups of input data. Each group occupies one row and consists of two integers n (n <10000) and m (m <1000). The meanings of n and m are as described above.

Output

For each group of input data, the sum of the output columns, each test instance occupies a row, requires that the precision be kept with 2 decimal places.

Sample Input


81 4
2 2

Sample Output


94.73
3.41


[Plain] # include <stdio. h>
# Include <math. h>
 
Int main ()
{
Int I;
Int n;
Int m;
Float t;
Float sum;

While (scanf ("% d", & n, & m )! = EOF)
{
Sum = t = n * 1.0;
For (I = 1; I <m; I ++)
{
Sum + = sqrt (t );
T = sqrt (t );
}
Printf ("% 0.2f \ n", sum );
}
Return 0;

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