Questions about the Preg_replace () function reverse reference usage.

$Array 1=array (' id ' = ' 1 ', ' name ' = ' ' Xiao Wang '), array (' id ' = ' 2 ', ' name ' = ' Xiao Li ')); $strA = ' AA name CC DD '; $ Strb= '/\s+ (\w+) \s+/i '; $Html =preg_replace ($strB, $Array 1[0][' ${2} '], $strA); Echo $Html;

As shown above, back to reference ${2} It is no problem to write as follows:

$Html =preg_replace ($strB, ' ${2} ', $strA);

However, if I want to use this quoted string as the key name of the array, such as $array[' ${1} ']!. will be an error. How to solve this problem?
notice:undefined index:in F:\Web\wwwroot\CMS\TemplateClass.php on line 236

Reply to discussion (solution)

For php5.5, you can

$Array 1 = Array (    ' id ' = ' 1 ', ' name ' = = ' Xiao Wang '),    array (' id ' = ' 2 ', ' name ' = ' Xiao Li '))    ; $strA = ' AA Name CC DD '; $strB = '/\s+ (\w+) \s+/ie '; $Html = preg_replace ($strB, ' $Array 1[0]["$"], $strA); Echo $Html;

For php5.3 and above, you can

$Array 1 = Array (    ' id ' = ' 1 ', ' name ' = = ' Xiao Wang '),    array (' id ' = ' 2 ', ' name ' = ' Xiao Li '))    ; $strA = ' AA Name CC DD '; $strB = '/\s+ (\w+) \s+/i '; $Html = Preg_replace_callback ($strB, function ($m) use ($Array 1) {return $Array 1[0 ] [$m [1];}, $strA); Echo $Html;

