"Android" to determine the existence of a shortcut to the principle--optimization of the online universal (10 times times faster)

1 principle: This is in 2.3 when the unintentional discovery, when I follow the example on the Internet to find out whether the shortcut is created when suddenly the application hangs, said to be a lack of permissions.

Com.android.launcher.permission.READ_SETTINGS or Com.android.launcher.permission.WRITE_SETTINGS

Then I added permissions, although it can be judged, but Xiaomi, HTC and other mobile phones can not be used, at this time suddenly found a piece of code on the Internet, only to understand the ideas of netizens, now to simple analysis, and make optimization.

String url = "content://" + Authority + "/favorites?notify=true";

In fact, the judgment shortcut is based on this contentprovider to judge. But we don't know about this authority, so how do we know? Query, according to Packagemanager get Providerinfo, and then determine whether the Providerinfo read and Write permission contains com.android.launcher.permission.READ_ SETTINGS or Com.android.launcher.permission.WRITE_SETTINGS.

We have understood this principle.

2 Solution: 1 This is the general wording of the Web:

public static Boolean Hasshortcut (context context, string appName) {string readsettingspermission = " Com.android.launcher.permission.READ_SETTINGS "; String authority = getAuthorityFromPermission2 (context, readsettingspermission); String url = "content://" + Authority + "/favorites?notify=true"; final Uri Content_uri = uri.parse (URL); Cursor C = context.getcontentresolver (). query (Content_uri, NULL, "Title=?", new string[] {appName}, NULL); if (c! = Nu ll && C.movetonext ()) {return true;} return false;} @SuppressLint ("Newapi") private static string GetAuthorityFromPermission2 (context context, String permission) {List <PackageInfo> packs = Context.getpackagemanager (). Getinstalledpackages (Packagemanager.get_providers); if ( Packs! = null) {for (PackageInfo pack:packs) {providerinfo[] providers = pack.providers;if (providers! = null) {for (Pro Viderinfo provider:providers) {if (Permission.equals (provider.readpermission)) return provider.authority;if ( Permission.equals (Provider.writepermission)) return provider.authority;}}} return null;}

2 This is my own way of thinking, although the idea came together, but a little bit in and out:

public static Boolean Hasshortcut (context context, string appName) {string readsettingspermission = " Com.android.launcher.permission.READ_SETTINGS "; String authority = getAuthorityFromPermission1 (context, readsettingspermission); String url = "content://" + Authority + "/favorites?notify=true"; final Uri Content_uri = uri.parse (URL); Cursor C = context.getcontentresolver (). query (Content_uri, NULL, "Title=?", new string[] {appName}, NULL); if (c! = Nu ll && C.movetonext ()) {return true;} return false;} private static string GetAuthorityFromPermission1 (context context, string permission) {Activitymanager am = ( Activitymanager) Context.getsystemservice (Context.activity_service); list<runningappprocessinfo> Appprocessinfos = am.getrunningappprocesses (); for (int i = 0; i < Appprocessinfos.size (); i++) {Runningappprocessinfo appInfo = Appprocessinfos.get (i); list<providerinfo> info = Context.getpackagemanager (). Querycontentproviders (Appinfo.processname, AppInfo.uid , the packageManager.get_providers); if (info = null) {for (int j = 0; J < Info.size (); j + +) {Providerinfo Provider = Info.get (j); if (Permission.equals (provider.readpermission)) {return provider.authority;} if (Permission.equals (provider.writepermission)) {return provider.authority;}}}} return null;}

"Android" to determine the existence of a shortcut to the principle--optimization of the online universal (10 times times faster)