SPOJ 375 QTREE series-Query on a tree (tree link division), qtree-query

Source: Internet
Author: User

SPOJ 375 QTREE series-Query on a tree (tree link division), qtree-query

Question address: SPOJ 375
The first line of tree link generation!
It seems to be a very advanced data structure. In fact, it is to convert the side of the tree from the tree structure into a linear structure, so that you can use a data structure such as a line segment tree or a tree array for fast maintenance. So that the time is reduced to n * log (2 * n ).
This topic is maintained by the line segment tree.
The Code is as follows:

#include <iostream>#include <string.h>#include <math.h>#include <queue>#include <algorithm>#include <stdlib.h>#include <map>#include <set>#include <stdio.h>using namespace std;#define LL long long#define pi acos(-1.0)//#pragma comment(linker, "/STACK:1024000000")const int mod=1e9+7;const int INF=0x3f3f3f3f;const double eqs=1e-3;const int MAXN=10000+10;#define root 1, n, 1#define lson l, mid, rt<<1#define rson mid+1, r, rt<<1|1int Max[MAXN<<2], head[MAXN], cnt, n;int siz[MAXN], dep[MAXN], w[MAXN], top[MAXN], son[MAXN], fa[MAXN], tot;struct node{        int u, v, w, next;}edge[MAXN<<1];void add(int u, int v, int w){        edge[cnt].u=u;        edge[cnt].v=v;        edge[cnt].w=w;        edge[cnt].next=head[u];        head[u]=cnt++;}void init(){        memset(head,-1,sizeof(head));        cnt=0;        memset(dep,0,sizeof(dep));        memset(son,0,sizeof(son));        memset(Max,0,sizeof(Max));        tot=0;}void dfs1(int u, int p){        siz[u]=1;        for(int i=head[u];i!=-1;i=edge[i].next){                int v=edge[i].v;                if(v==p) continue ;                dep[v]=dep[u]+1;                dfs1(v,u);                fa[v]=u;                if(siz[v]>siz[son[u]]) son[u]=v;                siz[u]+=siz[v];        }}void dfs2(int u, int tp){        w[u]=++tot; top[u]=tp;        if(son[u]) dfs2(son[u],top[u]);        for(int i=head[u];i!=-1;i=edge[i].next){                int v=edge[i].v;                if(v!=son[u]&&v!=fa[u])                        dfs2(v,v);        }}struct Line_Tree{        void PushUp(int rt)        {                Max[rt]=max(Max[rt<<1],Max[rt<<1|1]);        }        void Update(int p, int x, int l, int r, int rt)        {                if(l==r){                        Max[rt]=x;                        return ;                }                int mid=l+r>>1;                if(p<=mid) Update(p,x,lson);                else Update(p,x,rson);                PushUp(rt);        }        int Query(int ll, int rr, int l, int r, int rt)        {                if(ll<=l&&rr>=r){                        return Max[rt];                }                int mid=l+r>>1, ans=0;                if(ll<=mid) ans=max(Query(ll,rr,lson),ans);                if(rr>mid) ans=max(ans,Query(ll,rr,rson));                return ans;        }}lt;int Query(int u, int v){        int f1=top[u], f2=top[v], ans=0;        while(f1!=f2){                if(dep[f1]<dep[f2]){                        swap(u,v);                        swap(f1,f2);                }                ans=max(ans,lt.Query(w[f1],w[u],root));                u=fa[f1];f1=top[u];        }        if(u==v) return ans;        if(dep[u]<dep[v]) swap(u,v);        return max(ans,lt.Query(w[son[v]],w[u],root));}int main(){        int m, q, i, u, v, T, x, c;        char s[10];        scanf("%d",&T);        while(T--){                scanf("%d",&n);                init();                for(i=1;i<n;i++){                        scanf("%d%d%d",&u,&v,&c);                        add(u,v,c);                        add(v,u,c);                }                dfs1(1,-1);                dfs2(1,1);                for(i=0;i<cnt;i+=2){                        u=edge[i].u;                        v=edge[i].v;                        if(dep[u]<dep[v]) swap(u,v);                        lt.Update(w[u],edge[i].w,root);                }                while(scanf("%s",s)!=EOF&&s[0]!='D'){                        if(s[0]=='C'){                                scanf("%d%d",&x,&c);                                u=edge[x-1<<1].u;                                v=edge[x-1<<1].v;                                if(dep[u]<dep[v]) swap(u,v);                                lt.Update(w[u],c,root);                        }                        else{                                scanf("%d%d",&u,&v);                                printf("%d\n",Query(u,v));                        }                }        }        return 0;}

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.