time-php distance A time countdown, there is error, how to solve???

  
   ';$end=strtotime('2018-8-16 00:00:00');$d=$end-$now;$y=floor($d/3600/24/30/12);$m=($d/3600/24/30)%12;$dt=($d/3600/24)%30;echo "距世界杯还有{$y}年{$m}个月{$dt}天";

How can you write if you have an error in writing this month?
Does this error have an effect?

Reply content:

  
   ';$end=strtotime('2018-8-16 00:00:00');$d=$end-$now;$y=floor($d/3600/24/30/12);$m=($d/3600/24/30)%12;$dt=($d/3600/24)%30;echo "距世界杯还有{$y}年{$m}个月{$dt}天";

How can you write if you have an error in writing this month?
Does this error have an effect?

DateTime can be used to calculate a diff of two dates very quickly and easily.

  
   diff($datetime2);list($y, $m, $d) = explode('-', $interval->format('%Y-%m-%d'));echo "距世界杯还有{$y}年{$m}个月{$d}天";

The key is the logic is unclear, February 1 to March 1 Whether it is one months or 28 (29) days?

There's a crooked way to get the worth. Date parsing, and 1970-1-1 comparison

https://3v4l.org/1QEbC

Why use time ()
Why not go to the wee hours of the day?

  $y =floor ($ D/3600/24/30/12); This year is a bit far-fetched, some months more than 30 days.  

If your machine time is not very bad, you should not have much error.

  $dt = ($d/3600/24)%30; There's something wrong with that.  

For a time, you can use the third-party library of Carbon for quick calculations.

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