Two arbitrary types of variables are exchanged using an exclusive or operation.

Two arbitrary types of variables are exchanged using an exclusive or operation.

In this article, we will use the C language to implement the function of exchanging two variables of any type. It is difficult to use C for any type. If it is C ++, we can easily use the template function:

template<class T> inline void      swap(T& t1, T& t2) {     T tmp;     tmp = t1;     t1 = t2;     t2 = tmp; }

First, use ^ to exchange two integers. The code is simple but not easy to understand.

a ^= b;b ^= a;a ^= b;

Some people say that this writing method is amazing, but what I want to say is that the exclusive or operation is a very common operation in computers. understanding this algorithm is the basis for mastering the difference or. you can use the following methods to understand ^ two integers:

Consider a and B as two Boolean types first, then a and B will have four combinations

0, 0 (1) a ^ = B; to 0, 0 (2) B ^ = a; to 0, 0 (3) a ^ = B; to 0, 0
1, 0 (1) a ^ = B; to 1, 0 (2) B ^ = a; to 1, 1 (3) a ^ = B; to 0, 1
0, 1 (1) a ^ = B; to 1, 1 (2) B ^ = a; to 1, 0 (3) a ^ = B; to 1, 0
1, 1 (1) a ^ = B; to 0, 1 (2) B ^ = a; to 0, 1 (3) a ^ = B; to 1, 1

After the three sentences are executed, the values in the four combinations are exchanged.

If the bitwise operation is unrelated to the adjacent values of BITs, the char type of the eight bits, the short of the 16 bits, and long can both be exchanged using ^.

Some people think that this exclusive or operation can only be used for integer type exchange. In fact, exclusive or operation is for binary. Since all data types in the computer are saved in binary format, of course, this operation can be used.Exchange any data type with an exclusive or operation.

My solution is as follows:

 1 #define XYZ_SWAP(i, j) \
   if (&i != &j)\ 2 {\ 3     switch(sizeof(i))\ 4     {\ 5     case 1:\ 6         *(char*)&i ^= *(char*)&j;\ 7         *(char*)&j ^= *(char*)&i;\ 8         *(char*)&i ^= *(char*)&j;\ 9         break;\10     case 2:\11         *(short*)&i ^= *(short*)&j;\12         *(short*)&j ^= *(short*)&i;\13         *(short*)&i ^= *(short*)&j;\14         break;\15     case 4:\16         *(long*)&i ^= *(long*)&j;\17         *(long*)&j ^= *(long*)&i;\18         *(long*)&i ^= *(long*)&j;\19         break;\20     case 8:\21         *(long long*)&i ^= *(long long*)&j;\22         *(long long*)&j ^= *(long long*)&i;\23         *(long long*)&i ^= *(long long*)&j;\24         break;\25     default:\26         for (int k = 0; k < sizeof(i); k++)\27         {\28             *((char*)&i + k) ^= *((char*)&j + k);\29             *((char*)&j + k) ^= *((char*)&i + k);\30             *((char*)&i + k) ^= *((char*)&j + k);\31         }\32         break;\33     }\34 }35  36 void main()37 {38     char ca = 10;39     char cb = 20;40     XYZ_SWAP(ca, cb);41  42     short sa = 10;43     short sb = 20;44     XYZ_SWAP(sa, sb);45  46     int ia = 10;47     int ib = 20;48     XYZ_SWAP(ia, ib);49  50     long long lla = 10;51     long long llb = 20;52     XYZ_SWAP(lla, llb);53  54     float fa = 10.01f;55     float fb = 2000.89f;56     XYZ_SWAP(fa, fb);57  58     double da = 10.01;59     double db = 2000.89;60     XYZ_SWAP(da, db);61  62     void* pa = &da;63     void* pb = &db;64     XYZ_SWAP(pa, pb);65 }

Here we use a macro definition to exchange two variables of different types. We also assume that long occupies 4 bytes.

 

How can I use bitwise XOR (^) to exchange the values of two numbers!

Int a = *;
Int B = *;
A = a ^ B;
B = B ^;
A = a ^ B;
The AB exchange can be realized.

How can we exchange two numbers without variables? Guidance, implemented in C Language

Example:
# Include <stdio. h>
{
Int a = 2, B = 3;
A = a + B;
B = a-B;
A = a-B;
Printf ("a = % d, B = % d \ n", a, B );
}