Use PHP implementation to prevent users from uploading adult photos or topless, _php tutorial

Use the PHP implementation to prevent users from uploading adult photos or nude photos,

In this tutorial, we will learn how to prevent users from uploading adult photos or nude photos via PHP.

I stumbled upon a very useful phpclasses.org that was developed by Bakr Alsharif to help developers detect nude photos of pictures based on their skin pixels.

It analyzes the colors used in different parts of a picture and determines whether they match the color tones of the human skin.

As a result of the analysis, he returns a score that reflects the likelihood that the image will contain nudity.

In addition, he can output images that have been analyzed, which mark the pixels of the skin color using a given color.

Currently it can analyze png,gif and JPEG images.

Php
The following shows how to use this PHP class.

Let's start with a nf.php file containing a nude filter.

Copy the Code code as follows:
Include (' nf.php ');

Next, create a new class called ImageFilter, and then put it in a variable called $filter.

Copy the Code code as follows:
$filter = new ImageFilter;

Gets the image's score and puts it into a $score variable.

Copy the Code code as follows:
$score = $filter getscore ($_files[' img '] [' tmp_name ']);

If the image score is greater than or equal to 60%, then a message is displayed.

Copy the Code code as follows:
if ($score >= 60) {
/*message*/
}

Here is all the PHP code:

Copy the Code code as follows:
<?php
/*include the nudity Filter file*/
Include (' nf.php ');
/*create a new class called $filter */
$filter = new ImageFilter;
/*get the score of the image*/
$score = $filter getscore ($_files[' img '] [' tmp_name ']);
/*if the $score variable is set*/
if (Isset ($score)) {
/*if The image contains nudity, display image score and message. Score value if more than 60%, it's considered an adult image.*/
if ($score >= 60) {
echo "Image scored". $score. "%, It seems that you had uploaded a nude picture.";
/*if the image doesn ' t contain nudity*/
} else if ($score < 0) {
echo "Congratulations, you had uploaded an non-nude image.";
}
}
?>

Markup language
We can upload images using a basic HTML form.

Copy the Code code as follows:

Summarize
Please remember that PHP is not able to detect all nude images, so it is not fully trusted. I hope you think it's a little useful.

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