What to do in script to invoke the variables in PHP, as shown below

What to do in script to invoke the variables in PHP as follows:
What to do in script to invoke the variables in PHP as follows:

$strbbb = ' www.163.com ';
?>



Could have been in the 163 site, but my website is $strbbb, how to change it? I am not a computer professional, to this do not understand, please master advice

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Can't call! A client one server side!

But you can
$strbbb = ' www.163.com ';

echo "";

?>
I don't know if it counts!


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$strbbb = ' www.163.com ';
?>


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$strbbb = ' www.163.com ';
?>


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PHP Code

  
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I do not know the above several of the code has been tested no!
Throw aside the other simple

  
  

   
   

     JScript code 
    
 
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!--?  php 
 $strbbb = ' www.163.com '; 
?> 
 
 
 
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!--? php
 $strbbb = ' www.163.com '; 
? 
 
 
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 Less "http://" To jump to the directory of your current website "www.163.com", should be modified as follows. 
!--? PHP
 $strbbb = ' http://www.163.com '; 
? 
 
 
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 Cannot handle 
 var location = '!--? php print $strbbb?--  ';  
 if (Location.indexof ('://') ===-1) {
 location = '/http '/' +location; 
} 
 does not jump at all. 
 Change 
 
 you want to correct $strbbb can be in 
!--? php 
 $strbbb = ' http://www.163.com ';//can also be www.163.com 
?> 
 , why use JavaScript?

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!--? php $str = "ASDFA";?--"
 
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