Copy CodeThe code is as follows:
foreach ($array as & $row) {
$row = explode ('/', $row);
}
foreach ($array as $row) {
Do something
}
In this case, in the second loop there will be a logic error, adding the second loop where do something is the output $row, the output of the loop to the last is the penultimate element, not the last
To write like this.
Copy CodeThe code is as follows:
foreach ($array as & $row) {
$row = explode ('/', $row);
}
Unset ($row);
foreach ($array as $row) {
Do something
}
Or the first cycle of this.
Copy CodeThe code is as follows:
foreach ($array as $key = = $row) {
$array [$key] = explode ('/', $row);
}
say the principle.
The first loop uses the reference, and after the loop is finished, $row refers to the last element of the $array array, and when the second loop is started, the $row variable is assigned a new value each time the loop is used, in PHP, if a memory space is referenced, So when changing it is a direct change to the value of this memory space, that is, when the first loop of the second foreach, the value of the last element of the $array is changed to the value of the first element of the $array, the second loop, the second element is changed to a value, At the end of the second cycle, it is changed to the value of the second element, and the value of the last loop is necessarily the second value
Of course, if PHP's for loop has scope, this problem does not occur .....
http://www.bkjia.com/PHPjc/322706.html www.bkjia.com true http://www.bkjia.com/PHPjc/322706.html techarticle Copy the code code as follows: foreach ($array as} foreach ($array as $row) {//do something} is written so that a logic error in the second loop is added to the second loop where do something ... /c5>
