100 coppers = 1 silver 100 silver = 1 Gold
Want to write a money that's based on how many coppers return the corresponding level
For example, 102135铜币
the argument is that the return10金21银35铜
For example, 1544铜币
the argument is that the return15银44铜
etc...
PHP Foundation is not solid don't know how to write the most streamlined
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100 coppers = 1 silver 100 silver = 1 Gold
Want to write a money that's based on how many coppers return the corresponding level
For example, 102135铜币
the argument is that the return10金21银35铜
For example, 1544铜币
the argument is that the return15银44铜
etc...
PHP Foundation is not solid don't know how to write the most streamlined
/** * [format_every 换算进制到指定单位] * @param integer $number [需要换算数值] * @param integer $ary [每个单位之间的进制] * @param array $units [每个单位的描述] * @return [String] [格式化结果] */function format_every($number,$ary = 100,$units = array('铜', '银', '金')) { $format = ''; $prev = 0; for($i = count($units) - 1 ; $i >= 0 ; $i--){ if($next = floor($number / pow($ary, $i))){ $format .= $next - $prev * $ary . $units[$i]; } $prev = $next; } return $format;}//简单点的print_r(format_every(12345678));//1234金56银78铜//假如1坨=100金,则:print_r(format_every(12345678,100,array('铜', '银', '金','坨')));//12坨34金56银78铜//字节换算print_r(format_every(123456789,1024,array('B', 'KB', 'MB', 'GB', 'TB', 'PB')));//117MB755KB277B
function exchange($copper){ $gold = (int) ($copper / 10000); $silver = (int) ($copper / 100 - $gold * 100); $copper = $copper % 100; return array($gold, $silver, $copper);}
Simple to do. From the expedited the largest gold start processing, First division, then die, gold and Silver copper processing. When judging the output, make a judgment, the code is as follows:
0) { $result .= $gold ."金"; } if($sliver > 0) { $result .= $sliver ."银"; } if($cu > 0) { $result .= $cu ."铜"; } return $result; } //test echo level(102135); echo ""; echo level(1544); echo ""; echo level(99);
function level($money){ $ag = floor($money /100); $cu = $money % 100; $golden = floor($ag / 100); $ag = $ag % 100; echo "{$golden}金{$ag}银{$cu}铜币";}
It's very simple to write one.
def make_change(money, coins) dp = [0] path = [] result = {} coins.each_with_index do |coin, index| coin.upto(money) do |i| if !dp[i - coin].nil? && (dp[i].nil? || dp[i - coin] + 1 < dp[i]) dp[i] = dp[i - coin] + 1 coins[index] += 1 path[i] = i - coin end end end if path[money].nil? puts "impossible." and return end i = money loop do break if path[i].nil? result[i - path[i]] ||= 0 result[i - path[i]] += 1 i = path[i] end p result # 具体解endmake_change(102135, [10000, 100, 1])# => {1=>35, 100=>21, 10000=>10}
Well... I don't know if the calculation is fast or the string is faster.
结果: 10金币21铜币35银币
function Change () {
static $jin; static $yin; static $ton; if($number >= pow(10,4)){ $jin = intval($number/pow(10,4)); change($number -$jin*pow(10,4)); }else if($number >= pow(10,2)){ $yin = intval($number/pow(10,2)); change($number-$yin*pow(10,2)); }else{ $ton = $number; } return array($jin,$yin,$ton);}$number = 10110245;print_r(change($number));
/** * @param $coins int 币数 * @return string 格式化信息 */function coinFormatter($coins){ $coins = intval($coins); $jin = intval($coins/10000); $yin = intval($coins/100 - $jin*100); $tong = $coins%100; $info = ''; if($jin>0) { $info = $jin . "金"; } if($yin>0){ $info = $info.$yin."银"; } if($tong >0){ $info = $info.$tong."铜"; } return $info;}echo coinFormatter(114523);echo "\n";echo coinFormatter(523);echo "\n";echo coinFormatter(3);/*输出结果:11金45银23铜5银23铜3铜*/
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