# Why the result is the result below, please Daniel help explain

Source: Internet
Author: User
```
Why the result is the result below, please Daniel help explain  BOOL (TRUE)  Int (8)    Reply to discussion (solution)  \$a was assigned to the 6&& \$b =7  Original equivalent to \$ A = (6 && \$b =7)  returns BOOL (TRUE) because (6 && \$b =7) is True    \$a = 4; \$b = 5;if (\$a =6 && \$b =7) {//Because the priority of && is higher than = so it is \$a = (6 && \$b =7)    var_dump (\$a, \$b);//boo L (True) int (7)    \$a + +;//logical value does not have arithmetic, \$a does not change    \$b + +;//\$b plus a}echo var_dump (\$a, \$b);//bool (true) int (8)  Written in this way, should be able to help you understand (and the priority is lower than =)    \$a = 4; \$b = 5;if (\$a =6 and \$b =7) {    var_dump (\$a, \$b);//int (6) Int (7)    \$a + +;    \$b + +;} Echo var_dump (\$a, \$b);//int (7) Int (8)```
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