Why the result is the result below, please Daniel help explain

Source: Internet
Author: User
Why the result is the result below, please Daniel help explain
Int (8)

Reply to discussion (solution)

$a was assigned to the 6&& $b =7
Original equivalent to $ A = (6 && $b =7)
returns BOOL (TRUE) because (6 && $b =7) is True

$a = 4; $b = 5;if ($a =6 && $b =7) {//Because the priority of && is higher than = so it is $a = (6 && $b =7)    var_dump ($a, $b);//boo L (True) int (7)    $a + +;//logical value does not have arithmetic, $a does not change    $b + +;//$b plus a}echo var_dump ($a, $b);//bool (true) int (8)

Written in this way, should be able to help you understand (and the priority is lower than =)
$a = 4; $b = 5;if ($a =6 and $b =7) {    var_dump ($a, $b);//int (6) Int (7)    $a + +;    $b + +;} Echo var_dump ($a, $b);//int (7) Int (8)
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