The core of this question is to find the area of any polygon. We can use cross product to calculate. Take any one point and take two adjacent points clockwise to form two vectors with this point for cross product. All cross-border products obtained
[Cpp] # include # include # include # include # include using namespace std; void queue_list () {queue q1; int I; for (I = 0; I q2; // queue q2; int I; for (I = 0; I s2; int I; for (I = 0; I s1; // stack s1; int I; for (I = 0; I
Question: Give You n m and then give you n numbers. Let you divide the n numbers into m parts, and each part is continuous. Ask the minimum value of the maximum value in all parts. Practice: binary. At the beginning, the previous session was the sum
Beauty ContestTime Limit: 3000 MS Memory Limit: 65536 KTotal Submissions: 22893 Accepted: 6994 DescriptionBessie, Farmer John's prize cow, has just won first place in a bovine beauty autcontest, earning the title 'Miss Cow world '. as a result,
1 Preface events are mainly used for synchronization between threads. Unlike semaphores, events are characterized by one-to-many and many-to-many synchronization. That is, one thread can wait for multiple events to trigger: either of them can
[Html]/* Bubble Sorting: When two adjacent elements compare the first circle and end from the 0 badge, the maximum value captures the second circle for comparison, or starts from the 0 badge, the maximum value obtained in the first circle is not in
A: enumeration B: The game was A bit confusing. First, count the number of each letter. If there are x odd numbers, when x is = B), and then for B all take 1, a all take 0. E: There is a magical condition. Apart from node 1, the degree of other
What is the responsibility chain model? China of Responsibility: Enables multiple objects to process requests to avoid coupling between request senders and recipients. Connect the object to a chain and pass the request along the chain until an
Question [html] Description: print all numbers whose square is symmetric and whose values do not exceed n (n # include int judgesyry ry (int square); int main () {int I; for (I = 0; I = 0; j --) {if (arr [j]! = Arr [I-1-j]) {flag = 0; break ;}}
1. Why is a template class used in C ++? (1) It can be used to create a data structure with dynamic growth and reduction. (2) It is type-independent and therefore highly reusable. (3) It checks the data type during compilation rather than during
Use DFS to mark the adjacent @ characters and count the number of blocks. [Cpp] # include int m, n; char map [105] [105]; int dir [8] [2] = {-1,-1,-1, 0,-1, 1, 0,-1, // defines eight direction arrays 0, 1, 1,-1, 1, 0, 1, 1}; void dfs (int x, int y)
[Cpp] // clear orange OJ A1036. decomposition prime factor // http://www.tsinsen.com/ViewGProblem.page? Gpid = A1036 # include # include # define MAXS 10005 int main () {int a, B, I, j, k, count = 0, prime [MAXS], mark [MAXS] = {0 }, ans [MAXS];
Problem Description There are n people in Wuzhen, Tongxiang, Zhejiang province. Please find the first m monopoly in this town. the Input contains multiple groups of test cases. each use case contains two integers, n (0 # include # include #
Preface I caught a cold this weekend and never wrote a program. I got a question and practiced it. It is strange that this question can only be used as a global array. Passing parameters will always cause problems and gdb has not been debugged, this
Print? // Two Trust sites m_ListBox.AddString ("Hangzhou"); m_ListBox.AddString ("172.100.60.18") are added to ListBox; // two Trust sites m_ListBox.AddString ("172.100.60.8") are added to ListBox "); m_ListBox.AddString ("172.100.60.18"); [cpp]
When talking about GDB, we can't help but turn to its powerful functions. Among all the debuggers I have used, this is really a powerful debugging tool. Today I will talk about the simple usage of GDB. GDB is a powerful UNIX program debugging tool
[Cpp]/********************************** * ********** the subject is as follows: Q a B: query the sum of [a, B]; C a B x: update the range [a, B]; add x to all values of the range; algorithm idea: segment update of the Line Segment tree-delayed
[Cpp]/* question B. Question B: x, y, n; a (a> = 0), B (B # include # include using namespace std; int main () {double x, y, n; while (cin> x> y> n) {double p = 0, q = 1, a = 0, B = 1, ans = 99999999; while (B abs (a + 1)/B-x/y) a ++; if (abs (a/
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