Ultraviolet A 993: Product of digits

This question is very simple. First, use N to break down the factor with a prime number of, (that is, a prime number of less than 10) (first, we need to make a special judgment that N is not 1 ), then merge the factors that can be merged (for

Poj3348 Cows convex hull + Polygon Area Water question

/* Poj3348 Cows convex bag + Polygon Area Water question floor rounded down, returns double */# include # include # include using namespace std; const double eps = 1e-8; struct point {double x, y ;}; int n; point dian [10000 + 10], zhan [10000 + 10

Large number, high-precision calculation-subtraction of large numbers

A large number is a number that cannot be expressed by the Data Type in the algorithm language. The number of digits exceeds the range that can be expressed by the maximum data type. Therefore, when dealing with large numbers, you must first

Hdu 1199 Color the Ball (discretization line segment tree)

Color the BallTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission (s): 3529 Accepted Submission (s): 874   Problem DescriptionThere are infinite bils in a line (numbered 1 2 3 ....), and initially all of

Source program of TM1668 Led driver chip

# Inputs // data input port # defineP_1668DATLATA0 // data output port # defineP_1668CLKLATA1 # defineP_1668CSLATC0 # Signature = 1 # Signature = 0 # Signature = 1 # Signature = 0 # Signature = 0 # Signature = 1 # Signature = 0 // display mode

Hdu 2242 (dual Unicom + tree DP)

After the Tarjan double-link deflation point, you can choose one of them as the root node to find the number of byte points of all points + 1: m Then the difference between n-m and m is obtained, and the minimum value is

Learning summary --- topological sorting

What is topological sequence in topological sorting?Generally, such a linear sequence is called a sequence that satisfies the Topological Order. In short, a full order is obtained from a partial order on a set. This operation is called topological

CF 319B Psychos in a Line

Maintain a monotonically degraded queue. For each person, you only need to find the person in front of him and closest to him who can kill him. # Include # include # include # include using namespace std; # define N 100005 vector v; int f [N],

Sha 705 Slash Maze

Slash Maze By filling a rectangle with slashes (/) and backslashes (), you can generate nice little mazes. Here is an example:   As you can see, paths in the maze cannot branch, so the whole maze only contains cyclic paths and paths entering

CF 242E XOR on Segment

Two operations: 1. Calculate the range and 2. perform an exclusive or (xor) operation on each number in the interval If you directly maintain the interval sum, the Interval Update cannot be performed. Therefore, the information to be maintained is

Report on solving problems of the Version Controlled IDE

Question: give three operations 1. Insert a string at position p. 2. delete a string with a length of c from position p. 3. output the string whose length starts from position p in the v previous version to c. Solution: You can use the Balance

Sequential traversal of Binary Trees

# Include # include # include # include # include # include # include using namespace std; int a [20] [3]; void work1 (int x) //////////////////////////////////////// //// traverse {printf ("% d ", x); if (a [x] [1]! = 0) work1 (a [x] [1]);

POJ3928 and LA4329 tree Arrays

Use this question to test the effects of various practices ~ This is a question entitled "ACM2008" on the Beijing site. It is between simple and moderate. It is not enough for the penalty. Therefore, such a question must be answered. After adding (a

Va 10692-Huge Mod (exponential cycle)

#include #include #include #define LL long long LL a[20]; LL euler(LL n) { LL m=(LL)sqrt(n+0.5); LL ans=n; for(LL i=2;i1)ans=ans/n*(n-1); return ans; } LL pmod(LL a,LL n,LL m) { LL now = 1; for(LL

Hdu 4647 Another Graph Game, thought of as a water question ..

The question is to give an undirected graph, with each node having a bit of permission and edge permission. Then two children started to play the game. ALICE and BOB set ALICE to act first and then BOB, then take turns in turn. During the action,

Divide the edge weight into two halves and add them to the vertex weights of the two points associated with it.

1005: If no Edge Weight exists, the point weights are sorted in ascending order .. Consider the edge and divide the edge right into two halves to add the vertex right of the two points associated with it. .. Because when two people select

HDU 1358 Period

Question: What is the minimum cycle of the loop that exists in the string (the first part), and output all the prefix lengths that meet the condition and the minimum cycle lengths. # Include char P [1000010]; // int f [1000010] is stored from 0; //

POJ3264 Balanced Lineup

# Include # include # include # include # include # include // Accepted4868K3016MSC ++ 2390B2013-08-09 12:45:26/second ++ 2390B2013-08-09 12: 44: 44 using namespace std; const int maxn = 50100; const int INF = 0x7fffff; struct Node {int Left,

HDU1561: The more, The Better (tree DP + 01 backpack)

Problem DescriptionACboy is very fond of playing a strategic game. on a map, there are N castles, each of which has certain treasures, in each game, ACboy allows him to conquer M castles and gain the treasures in them. However, due to the

Log File C ++ time file lines

# Include # Include # Include # Define Line _ LINE __# Define File _ FILE __ Void WriteLog (const char * file, int line, char * msg){SYSTEMTIME st;GetLocalTime (& st );FILE * fp;Fp = fopen ("D: \ log.txt", "");Fprintf (fp, "MyLogInfo: % d-% d: % d %

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