java實現ip檢查

來源:互聯網
上載者:User

以前項目用到的要求實現IP存取控制,具體轉自哪裡忘記了,以為拿過來後自己又改了點。直接上代碼

public class ipTest {    /**     * 判斷IP是否在指定範圍;     */    boolean i;    public static boolean ipIsValid(String ipSection, String ip) {        if (ipSection == null)            throw new NullPointerException("IP段不可為空!");        if (ip == null)            throw new NullPointerException("IP不可為空!");        ipSection = ipSection.trim();        ip = ip.trim();        final String REGX_IP = "((25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)\\.){3}(25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)";        final String REGX_IPB = REGX_IP + "\\-" + REGX_IP;        if (!ipSection.matches(REGX_IPB) || !ip.matches(REGX_IP))            return false;        int idx = ipSection.indexOf('-');        String[] sips = ipSection.substring(0, idx).split("\\.");        String[] sipe = ipSection.substring(idx + 1).split("\\.");        String[] sipt = ip.split("\\.");        long ips = 0L, ipe = 0L, ipt = 0L;        for (int i = 0; i < 4; ++i) {            ips = ips << 8 | Integer.parseInt(sips[i]);            ipe = ipe << 8 | Integer.parseInt(sipe[i]);            ipt = ipt << 8 | Integer.parseInt(sipt[i]);        }        if (ips > ipe) {            long t = ips;            ips = ipe;            ipe = t;        }        return ips <= ipt && ipt <= ipe;    }    public static void main(String[] args) {        if (ipIsValid("10.118.128.0-10.118.255.255", "10.118.202.2")) {            System.out.println("ip屬於該網段");        } else            System.out.println("ip不屬於該網段");    }}

簡單說下思路,ipv4是長度為32位劃分成4段。那麼就把起止IP及要校正的IP的每段分別升位,不足8位末尾補0,全部升位後,在需要校正的IP是否在此段中即可。

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