CREATE OR REPLACE TYPE str_split IS TABLE OF VARCHAR2 (4000);CREATE OR REPLACE FUNCTION splitstr(p_string IN VARCHAR2, p_delimiter IN VARCHAR2) RETURN str_split PIPELINEDAS v_length NUMBER :=
database link ORA-01017: invalid username/password Today I create a database link in Oracle as followsCREATE DATABASE LINK DATABASE_LINK1CONNECT TO SCOTT IDENTIFIED BY TIGERUSING ‘PDTT’;When I try to use the link I get an error.select * from
一.B樹索引0. B樹索引中不存在非唯一的條目。1) 在非唯一索引中,ORACLE會把rowid作為一個額外的列追加到鍵上,使得鍵唯一。Exp:create index I on T( x , y ) ,從概念上講就是Create unique index I on T(x , y , rowid)。ORACLE會首先按索引索引值排序,然後再按照rowid升序排序。2) 在唯一索引中,資料只按索引索引值排序。1. 大多數情況下,B樹索引的高度都是2或者3,
二、以形參的形式定義和使用記錄、物件類型在用作形式參數時,記錄類型和物件類型有很多相同之處。在將它們作為遊標、函數或過程的形式參數以前,事先都必須定義一個記錄類型或者物件類型。如下例所示: 記錄DECLARE -- Define a record type. TYPE individual_record IS RECORD (individual_id INTEGER ,first_name VARCHAR2(30 CHAR) ,middle_initial
ORA-00604 error occurred at recursive SQL level stringCause:An error occurred while processing a recursive SQL statement (a statement applying to internal dictionary tables).Action:If the situation described in the next error on the stack can be