KMP【整理】

學習資料【KMP】Matrix67: http://www.matrix67.com/blog/archives/115【拓展KMP】劉雅瓊ppt: http://wenku.baidu.com/view/8e9ebefb0242a8956bece4b3.html【淺析“最小標記法”思想在字串迴圈同構問題中的應用--03 周源】:1.論文   2.pptkmp暫時告一段落,做了剛好一個星期,收集的各種Google加Baidu刨出來的KMP題目。還有兩題目前還沒想法,說不定哪天突然靈感來了再補上。

poj 1733 Parity game(帶權並查集)

連結:http://poj.org/problem?id=1733題目:DescriptionNow and then you play the following game with your friend. Your friend writes down a sequence consisting of zeroes and ones. You choose a continuous subsequence (for example the subsequence from the

HDU 3038 How Many Answers Are Wrong? (帶權並查集)

連結:http://acm.hdu.edu.cn/showproblem.php?pid=3038題目:Problem DescriptionTT and FF are ... friends. Uh... very very good friends -________-bFF is a bad boy, he is always wooing TT to play the following game with him. This is a very humdrum game. To

UVa 311 – Packets

連結:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=113&page=show_problem&problem=247原題:A factory produces products packed in square packets of the same height h and of the sizes  ,  ,  ,  , ,  . These

UVa 757 – Gone Fishing

【題目連結】http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=113&page=show_problem&problem=698【原題】John is going on a fishing trip. He has h hours available ( ), and there are n lakes in the area ( ) all

poj 3080 Blue Jeans(KMP匹配,枚舉子串)

連結:http://poj.org/problem?id=3080題目大意:給出m(2<=m<=10)個DNA序列, 求出這m個序列中最長的公用字串。如果有多個相同長度的,輸出字典序最小的。分析與總結:依次枚舉所有的子串, 然後再看是否在所有序列中都能夠匹配。儲存下長度最大且字典序最小的序列。代碼:#include<iostream>#include<cstdio>#include<cstring>using namespace

poj 1703 Find them, Catch them(種類並查集)

連結:http://poj.org/problem?id=1703題目:Find them, Catch themTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 22289 Accepted: 6648DescriptionThe police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO

【演算法導論】排序 (三):快速排序 深入分析

五、快速排序快速排序是最常用的一種排序演算法,包括C的qsort,C++和Java的sort,都採用了快排(C++和Java的sort經過了最佳化,還混合了其他排序演算法)。快排最壞情況O( n^2 ),但平均效率O(n lg n),而且這個O(n lg

HDU 2818 Building Block, poj 1988 Cube Stacking(帶權並查集)

連結:HDU: http://acm.hdu.edu.cn/showproblem.php?pid=2818POJ:  http://poj.org/problem?id=1988題目:Problem DescriptionJohn are playing with blocks. There are N blocks (1 <= N <= 30000) numbered 1...N。Initially, there are N piles, and each pile

poj 1182 食物鏈(經典!種類並查集)

連結:http://poj.org/problem?id=1182原題:Description動物王國中有三類動物A,B,C,這三類動物的食物鏈構成了有趣的環形。A吃B, B吃C,C吃A。 現有N個動物,以1-N編號。每個動物都是A,B,C中的一種,但是我們並不知道它到底是哪一種。 有人用兩種說法對這N個動物所構成的食物鏈關係進行描述: 第一種說法是"1 X Y",表示X和Y是同類。 第二種說法是"2 X

UVa 10718 – Bit Mask

【連結】http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=113&page=show_problem&problem=1659【原題】In bit-wise expression, mask is a common term. You can get a certain bit-pattern using mask. For example, if you

UVa 10405 – Longest Common Subsequence,最長公用子序列模板題

【連結】http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=114&page=show_problem&problem=1346【原題】Problem C: Longest Common SubsequenceSequence 1:                Sequence 2:                Given two sequences of

uva 1382 – Distant Galaxy

題目連結1. 座標值比較大,所以離散化座標2. 座標的絕對值不超過10^9,說明可能有負數,所以把全部座標移動轉換為正數(加上10^9)3. mat[i][j] ,表示(0,0) (i, j)為對頂點矩形之內包括邊界上有多少個點。4. 枚舉矩形的上下界,然後選擇左右邊界。 對於確定的左邊界left和右邊界right, 假設是的R3是left,  L3是right,那麼數量為:L1 + L2 + L3 - (R1+R2) + R3.   為了要使得以L3為右邊界的矩形上的點最多,那麼應該使得 R3

UVa 127 – “Accordian” Patience 資料結構專題

127 - "Accordian" Patience題目連結:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=63題目類型: 資料結構, 鏈表題意:發一副牌(52張,分兩行), 從左往右開始,

poj 2912 Rochambeau

連結:http://poj.org/problem?id=2912題目:DescriptionN children are playing Rochambeau (scissors-rock-cloth) game with you. One of them is the judge. The rest children are divided into three groups (it is possible that some group is empty). You don’t know

UVa 11129 – An antiarithmetic permutation

【連結】http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=113&page=show_problem&problem=2070【原題】A permutation of n+1 is a bijective function of the initial n+1 natural numbers: 0, 1, ... n. A permutation p is

UVa 529 – Addition Chains ,迭代加深搜尋+減枝

題目連結:UVA :http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=470POJ : http://poj.org/problem?id=2248類型: 回溯, 迭代加深搜尋, 減枝原題:An addition chain for n is an integer sequence  with the

HDU 4333 Revolving Digits(拓展KMP)

連結:http://acm.hdu.edu.cn/showproblem.php?pid=4333題目大意:給一個數字字串S,  可以把S最後一個數字移動到最前面變成另一個數字。例如123,  經過移動依次變成312,231,123。 注意當移動次數正好和S長度相等時,S又變回了最開始的那個數字。求這個移動過程所形成的所有字串,大於S(最初的)的數字,等於S,以及小於S的各有多少個。分析與總結:1.

UVa 784 – Maze Exploration 搜尋專題

784 - Maze Exploration775841.30%232884.06%題目連結:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=105&page=show_problem&problem=725題目類型: 搜尋範例輸入:2XXXXXXXXXX X XX * XX X XXXXXXXXXXX XX XX

poj 1611 The Suspects(並查集)

連結:http://poj.org/problem?id=1611題目:The SuspectsTime Limit: 1000MS Memory Limit: 20000KTotal Submissions: 15926 Accepted: 7622DescriptionSevere acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global

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