1、當Server來不及處理時,能緩衝多大資料?[Server]procedure TFormServer.UDPServer_MainUDPRead(Sender: TObject; AData: TStream; ABinding: TIdSocketHandle);begin ShowMessage('Hold');end;[Client]procedure TForm2.Button1Click(Sender: TObject);var
// How Many Fibs? (斐波那契計數)// PC/UVa IDs: 110601/10183, Popularity: B, Success rate: average Level: 1// Verdict: Accepted// Submission Date: 2011-05-30// UVa Run Time: 0.012s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net////
// How Many Pieces of Land? (土地分割)// PC/UVa IDs: 110602/10213, Popularity: B, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-06-01// UVa Run Time: 0.888s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 一個圓被圓上 n
// Counting (數數)// PC/UVa IDs: 110603/10198, Popularity: B, Success rate: high Level: 2// Verdict: Accepted// Submission Date: 2011-06-02// UVa Run Time: 0.032s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 假設 F(n) 表示使用 1,2,3,4 構建的和為 n
// Expressions (括號運算式)// PC/UVa IDs: 110604/10157, Popularity: C, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-06-03// UVa Run Time: 0.668s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 如何得到相應的遞推關係?翻看了 Catalan
// LC-Display (液晶顯示屏)// PC/UVa IDs: 110104/706, Popularity: A, Success rate: average Level: 1// Verdict: Accepted // Submission Date: 2011-04-09// UVa Run Time: 0.012s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net#include <iostream>#include
// Servicing Stations (服務站)// PC/UVa IDs: 110804/10160, Popularity: B, Success rate: low Level: 3// Verdict: Accepted // Submission Date: 2011-08-10// UVa Run Time: 0.056s// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 該題目的實質是求圖的最小支配集頂點個數。求圖的最小支配集問題是
// Tug of War (拔河)// PC/UVa IDs: 110805/10032, Popularity: B, Success rate: low Level: 2// Verdict: UVa Online Judge - Wrong answer, Programming-Challenges - Solved// Submission Date: 2011-08-09// Programming-Challenges Run Time: 0.020s//// 著作權(C)201
// Factovisors (階乘與整除)// PC/UVa IDs: 110704/10139, Popularity: A, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-06-11// UVa Run Time: 0.312s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 思路比較簡單,計算數 m 和數 2 - n 的 GCD,若
// Garden of Eden (伊甸園)// PC/UVa IDs: 110806/10001, Popularity: B, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-08-11// UVa Run Time: 0.660s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net////
// Summation of Four Primes (四素數之和)// PC/UVa IDs: 110705/10168, Popularity: A, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-06-11// UVa Run Time: 0.128s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net////
// Complete Tree Labeling (完全樹標號)// PC/UVa IDs: 110605/10247, Popularity: C, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-06-06// UVa Run Time: 0.172s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 如何得到遞推關係?設
// Graphical Editor (圖形化編輯器)// PC/UVa IDs: 110105/10267, Popularity: B, Success rate: low Level: 1// Verdict: Accepted// Submission Date: 2011-05-16// UVa Run Time: 0.060s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net#include <iostream>#include &
// Reverse and Add (反轉相加)// PC/UVa IDs: 110502/10018, Popularity: A, Success rate: low Level: 1// Verdict: Accepted// Submission Date: 2011-05-27// UVa Run Time: 0.028s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 利用動態數組來儲存數位每一位,逆序存放。#include <
// Colour Hash (色彩繽紛遊戲)// PC/UVa IDs: 110807/704, Popularity: B, Success rate: average Level: 3// Verdict: Accepted// Submission Date: 2011-08-28// UVa Run Time: 0.048s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 若從給定狀態進行單向搜尋,由於狀態較多,容易
// A Multiplication Game (乘法遊戲)// PC/UVa IDs: 110505/847, Popularity: A, Success rate: high Level: 3// Verdict: Accepted// Submission Date: 2011-05-29// UVa Run Time: 0.012s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 假設最終數為 162,為了防止對方得到大於等於
// Ones (僅由 1 組成的數)// PC/UVa IDs: 110504/10127, Popularity: A, Success rate: high Level: 2// Verdict: Accepted// Submission Date: 2011-05-29// UVa Run Time: 0.008s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 利用求模運算。(x * y + 1) mod n = ((x mod n)
// Polynomial Coefficients (多項式係數)// PC/UVa IDs: 110506/10105, Popularity: B, Success rate: high Level: 1// Verdict: Accepted// Submission Date: 2011-05-29// UVa Run Time: 0.024s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 多項式定理的應用。多元多項式 (a + b +
// Carmichael Numbers (Carmichael 數)// PC/UVa IDs: 110702/10006, Popularity: A, Success rate: average Level: 2// Verdict: Accepted// Submission Date: 2011-06-10// UVa Run Time: 0.336s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 此題關鍵是應用求模公式 x^y
// Euclid Problem (歐幾裡德問題)// PC/UVa IDs: 110703/10104, Popularity: A, Success rate: average Level: 1// Verdict: Accepted// Submission Date: 2011-06-10// UVa Run Time: 0.684s//// 著作權(C)2011,邱秋。metaphysis # yeah dot net//// 根據 Euclid 求 GCD 的過程,可以找到兩個數