POJ 3349 Snowflake Snow Snowflakes (hash 尋找)

Snowflake Snow SnowflakesTime Limit: 4000MS Memory Limit: 65536KTotal Submissions: 27156 Accepted: 7156DescriptionYou may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your

hdu 4490 Mad Veterinarian ( BFS+鏈表記錄路徑 )

題目連結:http://acm.hdu.edu.cn/showproblem.php?pid=4490Mad VeterinarianTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 279    Accepted Submission(s): 111Special JudgeProblem DescriptionMad

ZOJ 3018 Population(二維線段樹?矩形樹?)

地址:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3018題意:在平面內最多又32768個點,現在有兩種操作,1:在一些點上加上一個數n,2:詢問一個矩形地區內的點的數的和分析:這題一看像線段樹,想離線搞,發現不好處理,也許可以,不過我是做不來了,後來自己YY了下二維的線段樹,從來沒寫過=

ZOJ 3016 Cut(離散化+最小產生樹)

地址:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3016題意:給你n條線段,這些線段都平行於座標軸,沒有線段重疊,但是有交點,切割每條線段有一個值,現在這些線段形成一些封閉的區間,問怎樣切割使得所有點之間有通路,且花費最小分析:這題拋掉線段的外殼,很容易發現每個格子是一個點,外面的平面是一個點,點之間的邊正好是切割線段的花費,答案明顯的是最小產生樹的值。。。不過這些線段怎麼處理成小格子,頭疼=

女生應該找一個玩ACM的男生

轉自:http://blog.csdn.net/woshi250hua/article/details/7872081           1、強烈的事業心將來,他也一定會有自己熱愛的事業。而且,男人最性感的時刻之一,就是他專心致志做事的時候。所以,找一個機會在他全神貫注玩ACM的時候,從側面好好觀察他,你就會發現我說的話沒錯。    2、永不放棄的精神在比賽剛開始,神牛隊就飄崎嶇。玩ACM的男生不會退縮,而是毅然決定一個人繼續AC下去,靠著自己對勝利的渴望,拿下一個氣球、兩個氣球、三個氣球……

hdu 2955 Robberies (0 1背包)

RobberiesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8096 Accepted Submission(s): 3063Problem DescriptionThe aspiring Roy the Robber has seen a lot of American movies, and knows that the bad

hdu 4571 Travel in time ( 圖論+動態規劃 )

Travel in timeTime Limit: 8000/4000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 971 Accepted Submission(s): 196Problem Description  Bob gets tired of playing games, leaves Alice, and travels to Changsha alone.

poj 3694 (求橋+LCA問題)

NetworkTime Limit: 5000MS Memory Limit: 65536KTotal Submissions: 3868 Accepted: 1321DescriptionA network administrator manages a large network. The network consists of N computers and M links between pairs of computers. Any pair of computers are

poj 3229 The Best Travel Design ( 圖論+狀態壓縮 )

The Best Travel DesignTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 1359 Accepted: 340DescriptionDou Nai is an excellent ACM programmer, and he felt so tired recently that he wants to release himself from the hard work. He plans a travel

poj 1163 The Triangle (動態規劃入門題)

The TriangleTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 33836 Accepted: 20105Description73 88 1 02 7 4 44 5 2 6 5(Figure 1)Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers

HDU 4568 Hunter ( TSP + 狀態壓縮 )

HunterTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 529 Accepted Submission(s): 153Problem Description  One day, a hunter named James went to a mysterious area to find the treasures. James

poj 2420 A Star not a Tree?(類比退火求費馬點)

A Star not a Tree?Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 2519 Accepted: 1332DescriptionLuke wants to upgrade his home computer network from 10mbs to 100mbs. His existing network uses 10base2 (coaxial) cables that allow you to

POJ 1159 Palindrome (動態規劃)

PalindromeTime Limit: 3000MS Memory Limit: 65536KTotal Submissions: 48269 Accepted: 16570DescriptionA palindrome is a symmetrical string, that is, a string read identically from left to right as well as from right to left. You are to write a program

各大OJ題目分類

源地址http://blog.csdn.net/linleiqin/article/details/5637647收藏以後深入練習,近期恐怕是搞不定了。。。-----------------------------最佳化問題------------------------------------- ----------------------常規動態規劃  SOJ1162 I-Keyboard  SOJ2096 Maximum Submatrix  SOJ2111 littleken

hdu 4435 charge-station  (貪心+圖論)

charge-stationTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 587 Accepted Submission(s): 291Problem DescriptionThere are n cities in M^3's empire. M^3 owns a palace and a car and the palace

轉:二分圖最大匹配Hopcroft_Karp演算法

 二分圖最大匹配除了匈牙利演算法還有一個Hopcroft-Karp演算法,匈牙利演算法的複雜的為O(ne),而Hopcroft-Karp演算法的複雜度為O(en^0.5)。     該演算法的精髓在於同時找多條增廣路進行反轉。我們先用BFS找出可能的增廣路,這裡用到BFS層次搜尋的概念,記錄當前結點在第幾層,用於後面DFS沿增廣路反轉時用,然後再用DFS沿每條增廣路反轉。這樣不停地找,直至無法找到增廣路為止。     wiki上的說明: http://en.wikipedia.org/wiki/

hdu 1081 To The Max ( 最大子矩陣 )

To The MaxTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6612 Accepted Submission(s): 3159Problem DescriptionGiven a two-dimensional array of positive and negative integers, a sub-rectangle is

poj2488 A Knight’s Journey(簡單dfs)

給出一個國際棋盤的大小,判斷馬能否不重複的走過所有格,並記錄下其中按字典序排列的第一種路徑。注意字典序。#include<iostream>#include<cstdio>#include<cstring>using namespace std;int dx[8]= {-1,1,-2,2,-2,2,-1,1};//按字典順序走必須這麼寫int dy[8]= {-2,-2,-1,-1,1,1,2,2};int

ural 1519(插頭DP入門題)

1519. Formula 1Time Limit: 1.0 secondMemory Limit: 16 MBBackgroundRegardless of the fact, that Vologda could not get rights to hold the Winter Olympic games of 20**, it is well-known, that the city will conduct one of the Formula 1 events. Surely,

poj 3074(數獨 Dancing Link精確覆蓋)

SudokuTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 5830 Accepted: 1839DescriptionIn the game of Sudoku, you are given a large 9 × 9 grid divided into smaller 3 × 3 subgrids. For example,.2738..1..1...6735.......293.5692.8...........6.174

總頁數: 61357 1 .... 19641 19642 19643 19644 19645 .... 61357 Go to: 前往

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