LeetCode Count Complete Tree Nodes,leetcodenodes LeetCode Count Complete Tree Nodes題目思路這個樹會灰常的大; 先沿著左右兩遍計算深度,如果深度一樣直接代公式算; 如果深度不一樣,那就找最下面一層的斷點;代碼int maxD, num;int calDeepFromRight(struct TreeNode* root) { int ans = 0; while (root) {
POJ 1469 COURSES (二分圖最大匹配 匈牙利演算法),poj1469COURSESTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 18892 Accepted: 7455DescriptionConsider a group of N students and P courses. Each student visits zero, one or more than one courses.
POJ 1325 Machine Schedule (二分圖最小點集覆蓋 匈牙利演算法),poj1325Machine ScheduleTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 12621 Accepted: 5399DescriptionAs we all know, machine scheduling is a very classical problem in computer
Codeforces Round #306 (Div. 2) (ABCE題解),比賽連結:http://codeforces.com/contest/550A. Two Substringstime limit per test2 secondsmemory limit per test256 megabytesYou are given string s. Your task is to determine if the given strings contains two
Codeforces 549G. Happy Line 貪心,codeforces549g很有意思的貪心:Let's reformulate the condition in terms of a certain height the towers, which will be on the stairs. Then an appropriate amount of money of a person in the queue is equal to the height of the
POJ 1466 Girls and Boys (匈牙利演算法 最大獨立集),poj1466Girls and BoysTime Limit: 5000MS Memory Limit: 10000KTotal Submissions: 10912 Accepted: 4887DescriptionIn the second year of the university somebody started a study on the romantic relations
C++勝者樹,勝者樹 #include <iostream>#define MAX_VALUE 0x7fffffffusing namespace std;//在這裡我先反思一下,不知道怎麼搞的,這個演算法耗費我3個小時,慘不忍睹。void DealWhat(int b[],int n,int flags)//每一次在n位置調整該位置的與子樹的大小關係。{ int left = 2 * n + 1; int right = 2 * n + 2; if
python下MySQLdb用法執行個體分析 本文執行個體講述了python下MySQLdb用法。分享給大家供大家參考。具體分析如下: 下載安裝MySQLdb ① linux版本 http://sourceforge.net/projects/mysql-python/ 下載,在安裝是要先安裝setuptools,然後在下載檔案目錄下,修改mysite.cfg,指定本地mysql的mysql-config檔案的路徑 ②