HDU 5063 Operation the Sequence(暴力),hdu5063HDU 5063 Operation the Sequence題目連結把操作存下來,由於只有50個操作,所以每次把操作逆回去運行一遍,就能求出在原來的數列中的位置,輸出即可代碼:#include <cstdio>#include <cstring>#include <algorithm>using namespace std;typedef long long
C++ 之 exception,exception本文講關於C++的異常的所有東西:絕對不讓異常逃離解構函式阻止exception逃離解構函式,主要是兩個原因:1 防止在異常處理過程中的棧展開行為時,將調用terminate函數。程式將會結束,有時候其實錯誤並沒有那麼嚴重。[插入: 什麼時候會調用terminate函數呢?][回答 : By default, the terminate handler calls abort. But this behavior can be
newLISP資料擬合,newlisp資料擬有時候需要擬合資料,比如某周五的資料因故無法產生, 可以用下面的演算法簡單擬合。計算前兩周的周四,周五的環比(鄰比), 兩個鄰比求平均後加1, 乘以 周四的資料,得到周五的資料。用newLISP實現代碼很簡單:參考下面的樣本:#!/usr/bin/newlisp(define (adjacent-div a b) (div (sub b a) a))(define (average a b) (div (add a b) 2))(define (
Python 小程式,對檔案操作及其他,下面是自己寫的幾個對檔案操作的小程式,裡面涉及到檔案操作,列表(集合,字典)的運用等。比如說,從檔案中讀取一行資料,分別存放於列表中,再對列表進行操作,如去掉裡面的重複項,排序等操作。常見對檔案中行進行操作:#這裡列出兩個常用的方法方法01: 一次性讀取所有行>>> f = file('1.txt')>>> while 1:lines = f.readlines()if not
leetcode 鏈表 Partition List,leetcodepartitionPartition List Total Accepted: 19761 Total Submissions: 73252My SubmissionsGiven a linked list and a value x, partition it such that all nodes less than x come before
zoj 3822 Domination(2014牡丹江地區賽D題),zoj牡丹江DominationTime Limit: 8 Seconds Memory Limit: 131072 KB Special JudgeEdward is the headmaster of Marjar University. He is enthusiastic
Leetcode,leetcodeojAn kind of interesting problem. Use an array arr[] to store how many gas are left if we travel from station i to station i+1, arr[i] = gas[i] - cost[i]. Then it becomes an variance of the maximal sub array problem: if
POJ1422 Air Raid 【DAG最小路徑覆蓋】,poj1422dagAir RaidTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 6763 Accepted: 4034DescriptionConsider a town where all the streets are one-way and each street leads from one