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) memset (A,x,sizeof (a))#defineMP (x, y) make_pair (x, y)#definePB (x) push_back (x)using namespacestd;Const Long LongINF = 1e18+1LL;Const intINF = 1e9+1e8;Const intn=1e5+ -;Constll mod=1e9+7;intto[n1],nex[n1],head[n],tot=2;intSiz[n],son[n],tip[n],top[n],dep[n],fa[n],cnt=0;intn,m;ll C[n];mapint,int>M;voidAddintUintv) {To[tot]=v; Nex[tot]=Head[u]; Head[u]=tot++;}voidDFS1 (intUintf) {Siz[u]=1; Fa[u]=F; Dep[u

; - } to } ret; + intw[1000001],wei[1000001],fa[1000001]; - intnex[1000001],fir[1000001]; the BOOLvis[1000001]; * voidBuildintNowintfat) $ {Panax Notoginsengfa[now]=fat;vis[now]=1; - for(intI=fir[now];i;i=Nex[i]) the if(!vis[e[i].to]) + build (E[i].to,now); A } the intDfsintNow ) + { - for(intI=fir[now];i;i=Nex[i]) $ if(fa[e[i].to]==Now ) $w[now]^=DFS (e[i].to); - returnW[now]; - }

concil_set:if each in ans_attend_set:c Oncil_attend_set.add (each) elif each of Ans_notatt_set:concil_notatt_set.add (each) else:concil_n Otans_set.add (each) #3. Display result Def disp (SS, cap, num = True): #ss: List set #cap: Opening description print (Cap, ' ({}) '. Format (len (ss))) for I in rangE (Np.ceil (LEN (ss)/5). Astype (int)): Pre = i * 5 NEX = (i+1) * 5 #调整显示格式 dd = ' for Each in list (ss) [Pre:nex]: If Len (each) = = 2:DD = dd + "+ e

connects intersectionsAandBand has lengthD(1≤D≤5000)OutputLine 1:the length of the second shortest path between node 1 and nodeNSample Input4 41 2 1002 4 2002 3 2503 4 100Sample Output450Hint3 (length 100+250+100=450), 4 (length 100+200=300) and 1, 2, routes:1, 2SourceUsaco 2006 November Gold A short-circuit problem, just log to each point of the short circuit is OK, and then with each update of the shortest and minor short-circuit to continue to update his neighbor points. Code:#include #inclu

About the ORA-01002 read violation order, endloop carried out the loop value, but when JDBC calls the stored procedure, only need to return a result set (cursor) on the line, then About the ORA-01002 read violation order, the end loop carries out the loop value, but when JDBC calls the stored procedure, only need to return a result set (cursor) on the line, then Today, the following error occurs when you run your own JDBC to call the stored procedure:ORA-01002 read violation orderMost of th

(); - } - returnx; + } - Const intme =1000233; + intN; A inthead, tail; at int inch[me]; - intUe[me]; - intDe[me]; - intSi[me]; - intfat[me][ +]; - intTot, nex[2][me], fir[2][me], to[2][me]; inInlinevoidIns (intXintYintz) - { toNex[z][++tot] =Fir[z][x]; +FIR[Z][X] =tot; -To[z][tot] =y; the } *InlinevoidTopo () $ {Panax NotoginsengHead =0, tail =0; - for(inti =1; I i) the if(!inch[i]) +Ue[++tail] =i; A while(Head tail) the

directly 22 paired, because two points may not be able to reach each other, or should be in the $spfa$ to assign initial value run out.#include #defineOO 0x3f3f3f3fusing namespacestd;intN, m, tot;structNode {intu, V, NEX, W; Node (intU =0,intv =0,intNEX =0,intW =0): U (U), V (v), NEX (NEX), W (w) {}} edge[800005];intStot, h[100005];voidAddintUintVints) {edge[++s

# Include Using namespace STD;Int CNT = 0;Int flag = 0;Int to [400007], NEX [400007], vis [100007], head [100007];Void add (int A, int B) {// The head Insertion Method of the linked list. When the NEX array is opened to next, it will be compiled incorrectly.To [++ CNT] = B;Nex [CNT] = head [a];Head [a] = CNT;}Void DFS (int A, int B ){For (INT I = head [a]; I! = 0

> ::iterator iter;////map mp;//map ::iterator p;typedef struct Node {int fro,to;int nex;int val;};Node edge[100 * 4];int value[100 + 5];int head[100 + 5];bool vis[100 + 5];int dis[100 + 5];int father[100 + 5];int mark[100 + 5];int dp[100 + 5][500 + 5];int tot;int n,t;void init() {memset(head,-1,sizeof(head));memset(value,0,sizeof(value));memse

DP and linear DP are similar. DFS a bit.#include #include#include#include#includeusing namespacestd;intN;inthappy[6005];vectorint> son[6005];intdp[6005][3];intvis[6005];voidDfsintNow ) {dp[now][1] =Happy[now]; dp[now][0] =0; for(intI=0; I) { intNEX =Son[now][i]; DFS (NEX); dp[now][1] + = dp[nex][0]; dp[now][0] + = max (dp[nex][0],dp[

Title Description: Given a short string (without spaces), and given a number of strings, delete the contained short string in these strings. Input: Enter only 1 sets of data.Enter a short string (with no spaces), and then enter several strings until the end of the file. Output: Delete the input short string (case insensitive) and remove the whitespace, output. Sample input:

neighboring levels cannot be picked at the same time.The DP expression is: Dp[i][0]=∑max (dp[son][0],dp[son][1]); dp[i][1]=∑dp[son][0];But the problem is that there may be rings (at least 3 elements on the ring).If there is a ring, delete one of the edges in the ring, make a DP from two points on the side, and the final answer is Max (Dp[st][0],dp[en][0]), which means that two points cannot be taken at the same time.The problem may have multiple connected components, and not all connected compo

paths to the V-point and Shortest path +1 is _cnt[v]+=cnt[u]. If DIST[U]+E.WThen the final answer is equal to cnt[e] plus the shortest path number from the starting point to the I-point length of the shortest short-circuit length of +1 times the first point to the first I.#include #include#include#include#includestring>#include#include#includeusing namespaceStd;typedefLong Longll;Const intinf=0x3f3f3f3f;Const intmaxm=11000;Const intmaxn=1100;structedge{intV,w,

http://acm.hdu.edu.cn/showproblem.php?pid=5437Good understanding of the topic, if violent words or timeouts, you can consider the priority queue can be very simple to solve the problem1#include 2#include 3#include 4#include 5 using namespacestd;6 structPoint {7 intX,id;8 CharMax201];9 BOOL operatorConstPoint Q)ConstTen { One if(x==q.x)returnq.idID; A returnxq.x; - } - }; thePoint pe[150001]; - intnex[150001],a[150001]; - intMain () - { + intt,n,m,z,i,x,y,

that encapsulates the width and height of a componentDimension Dim = New Java.awt.Dimension (200, 30);//Set the size of the Textname componentTextname.setpreferredsize (Dim);Jf.add (textname);//Add textname to the formCreate an object of the JLabel class to show how to buyJLabel lableshopping = new Javax.swing.JLabel ("How to buy");Jf.add (lableshopping);//Add labelshopping to the formJPasswordField nextname = new Javax.swing.JPasswordField ();Dimension NEX