dex number lookup

How to deal with android methods that exceed 65536. the number of method references in a. dex file exceed 64 k, android. dexI. Problem description: The number of Dex file methods in the application exceeds the upper limit of 65536. In short, the application burst. Ii. solution: Solution 1: Use a plug-in framework such

: @ com.android.dx.command.dexer.Main.main (main.java:199) at Com.android.dx.command.Main.main (main.java:103)That's right. The number of Dex file methods in your app exceeds the maximum limit of 65536, so simply put, the app is bursting.So let's see why this error is caused:In the Android system. All the code for an App is inside a Dex file.

Android uses android-support-multidex to solve the problem of Dex exceeding the limit of the number of methods, so that your application will not burst into the dark. androidmultidex If you have reprinted, please declare the Source: sand: http://blog.csdn.net/t12x3456 (from the sand csdn blog) With the continuous iteration of applications and the expansion of business lines, applications become larger and l

One: Problem Description:The number of Dex file methods in the app exceeds the maximum of 65536, and in simple terms, the application is bursting.Second, the solution: Scenario 1: Using a plug-in framework such as: https://github.com/singwhatiwanna/dynamic-load-apkScenario 2: Split Dexthree: How to implement the split Dex file1. RELATED LINKSHttps://developer.and

Android uses android-support-multidex to solve the problem of Dex exceeding the limit on the number of methods, so that your applications will not burst With the continuous iteration of applications and the expansion of business lines, applications become larger and larger (such as integrating various third-party sdks or jar packages supported by the public, with high project coupling and repeated classes

: @ com.android.dx.command.dexer.Main.main (main.java:199) at Com.android.dx.command.Main.main (main.java:103)Yes, the number of Dex file methods in your app exceeds the maximum of 65536, so simply put, the app is bursting.So let's see why this error is caused:InAndroidSystem, aAppAll of the code is in aDexFile inside.Dexis a jar-like store that has manyJavaCompiles the archive file for the byte code. Beca

In an Android system, all the code for an app is inside a dex file. Dex is a jar-like archive that stores many Java-compiled bytecode. Because the Android system uses the Dalvik virtual machine, you need to convert the class file that was compiled with Java compiler into a class file that Dalvik can execute. The point here is that Dex, like the jar, is an archive

) Yes, the number of Dex file methods in your app exceeds the maximum of 65536, so simply put, the app is bursting. in the Android system, all the code for a App is in a Dex file. Dex is a jar-like archive that stores multiple Java compiled bytecode. Because the Android system uses the Dalvik vi

in the previous period of time doing Android projects, there has been a problem of more than 65535 methods, if the number of methods in the code is not more than 65535, you canadd a line to the Project.Properties file dex.force.jumbo=true, solve this problem. Later, referring to some methods on the Internet, I wrote a gadget to count the number of methods in jar packages and

//July 22, 2017#include #defineLEN 15intMain () {intN; voidBinsearch (int* p,intN); intarr[len]={98, the, the, the, the, -, $, Wu, +, the, the, $, *, to, in}; printf ("Please enter the number you want to find: \ n"); scanf ("%d",N); Binsearch (Arr,n); return 0;}voidBinsearch (int* p,intN) { intLow,high,mid; Low=0; High=len-1; while(lowHigh ) {Mid= (Low+high)/2; if(p[mid]==N) {printf ("%d is the value of the%d element of the array (subscript sta

Topic:Counts the number of occurrences of a number in a sorted array.Ideas:Because it is a well-ordered array, a binary lookup algorithm can be used.Generally the most easily thought of the idea is to use a binary search to find a first, and then go to his left and right side of the traverse, but this method because in the N array may also have n K, soThe complex

Topic:In the sorted array, find out the number of occurrences of a given numberIdeas:Since there is a sort array, it is easy to think of binary lookups, with time complexity O (LOGN);First, by binary find the leftmost occurrence of the number of the subscript left (if not found, then return-1), and then through the binary search find the rightmost occurrence of the numb