js backpack

world;Thanks to the opponents, they make us keep making progress and efforts.Likewise, we would like to thank the pain and hardship brought to our wealth ~ Input data first contains a positive integer c, which indicates that there is a C set of test cases, the first line of each set of test cases is two integers n and m (1Output for each set of test data, export the maximum weight that can be purchased for rice, and you can assume that you are spending more than all of the rice, and you c

Sumsets Time Limit: 2000MS Memory Limit: 200000K Total Submissions: 15045 Accepted: 5997 DescriptionFarmer John commanded his cows to search for different sets of numbers the sum to a given number. The cows use is numbers that is an integer power of 2. Here is the possible sets of numbers that sum to 7:1) 1+1+1+1+1+1+1 2) 1+1+1+1+1+2 3) 1+1+1+2+2 4) 1+1+1+4 5) 1+2+2+2 6) 1+2+4 Help FJ count all possible representations for a given i

There is a backpack can be put into the item weight of S, existing n items, the weight is w1,w2,w3,...wn. Ask if you can select several items from the N-item into the backpack, so that the sum of the weights placed is just s. If there is a choice to meet the conditions, then the backpack has a solution, or the knapsack problem is not solved.DescriptionFirst act i

Title: Uva-10280old Wine into New bottles (full backpack + pruning)The main topic: Now to put the old wine into the new bottle, each bottle has the smallest maximum capacity requirements, and then give you l wine, in the give you n bottles, each bottle of the specification also give you, each kind of bottle supply is unlimited, ask how to arrange these wine to make the remaining wine the least.Problem-solving ideas: The problem is a complete

This is a simple 01 backpack, but the knapsack problem is fairly simple, is the front of the details of the time to pay attention to, test instructions roughly said three restrictions bar1. Only A, B, c three types of invoices can be reimbursed, the other will not be reimbursed2. No more than 600 reimbursement for item items3. The total amount of each invoice does not exceed 1000With these three, there is one to be careful is the amount of reimburseme

-negative integerV P q(wherevindicates the price of the item (v),Pindicates the importance of the item ( 1~5 ),QIndicates whether the item is a main piece or an attachment. Ifq=0, indicating that the item is the main piece, ifq>0, indicating that the item is an attachment,Qis the number of the owning main part)outputs description output Description there is only one positive integer, which is the maximum value of the sum of the product of the price and the importance of the item not exceeding th

, respectively the smartness and funness for each cow.Output* Line 1:one integer:the optimal sum of TS and TF such that both TS and TF is non-negative. If no subset of the cows has non-negative TS and non-negative TF, print 0.Sample Input5-5 78-66-32 1-8-5Sample Output8HintOUTPUT DETAILS:Bessie chooses cows 1, 3, and 4, giving values of TS = -5+6+2 = 3 and TF= 7-3+1 = 5, so 3+5 = 8. Note that adding cow 2 would improve the valueof TS+TF to ten, but the new value of TF would was negative, so it's

View code /* Give you n items, each of which has a certain volume, give you a certain total volume of a certain backpack, ask you to use this backpack to install these items, there are several different combinations of items in a backpack. One combination is legal: The remaining backpack capacity must be the mini

Given n items with size a[i] and value v[i], and A backpack with size M. What's the maximum value can you put into the backpack?NoteYou cannot divide item in small pieces and the total size of items you choose should smaller or equal to M.ExampleGiven 4 items with size [2, 3, 5, 7] and value [1, 5, 2, 4], and a backpack with size 10.The maximum value is 9. Soluti

Test Instructions: The value of 1,2,3,4,5,6 items respectively a[1],a[2],a[3],a[4],a[5],a[6], ask can be divided into two piles of equal value. Solution: Convert to multiple backpacks1#include 2#include string.h>3#include 4#include 5 using namespacestd;6 7 intdp[120010];8 inta[Ten];9 Ten intNvalue; One A //0-1 backpack, at cost, to get the value of weight - voidZeroonepack (intCostintweight) - { the for(inti=nvalue;i>=cost;i--) -Dp[i]=max (dp[i]

/* Poj 1276 the meaning of multiple knapsack questions is probably given a currency m to be raised, given the number of currencies owned N [I] and the value V [I], q: How much can you raise is a multi-backpack problem DP [J] indicates the maximum number of valuable items that a backpack with a capacity of J can hold. Generally, the solution to multiple backpacks is to convert them. complete

Poj (2184) -- Cow Exhibition (01 backpack deformation) In fact, I don't think I have a deep understanding of this question. However, after doing this today, we will first record our current ideas. The general meaning of the question is: There is a nheaded ox, each of which has a s value representing the IQ value, and a f value representing its humorous value. Then, ask you what the total and maximum values of the IQ and humor values are, and ensure th

contains four numbers N (1 N M (1 W (1 W X (1 X lt;= N )-The starting point ofNitori.Then followed N by lines, each line contains the integers which means the shop on tourist attraction i sells the c2/> TVi and Things (1 TWi TVi Next, there is M lines, each line contains three numbers, Xi , Yi and Li , which means there is a one-way road From tourist attraction Xi to Yi , and the length is Li (1 Xi , Yi Li OutputFor each test case, output the answer as the description required.Sample Input4 4

There are n items and a backpack with a capacity of M, with unlimited pieces available for each item. The volume of the article I is weight, and the value is values. The solution of which items are loaded into the backpack allows the volume of these items to be no more than the backpack capacity, and the value of the largest sum.1 //"n" is the number of kinds.2 /

Description There are n items and a backpack with a capacity of V. The cost of item I is c[i], value is w[i]. These items are divided into groups, and items in each group conflict with each other, with a maximum of one selected. To find out what items to pack into the backpack can make the sum of these items does not exceed the backpack capacity, and the total va

Problem: There are n items and a backpack with a capacity of V. The cost of item I is c[i], value is w[i]. These items are divided into groups, and items in each group conflict with each other, with a maximum of one selected. To find out what items to pack into the backpack can make the sum of these items does not exceed the backpack capacity, and the total value

Title Link: https://vjudge.net/problem/POJ-1276Test instructions: There are now cash, and n kinds of coins, each coin has NI, the value of Di, for all kinds of coins composed of not more than cash of the largest amount of money ....Idea: binary split into 01 backpack, or converted to a full backpack are all possibleFull backpack://This problem can let w,v start f

01 BackpackThere are n different items, each item has two attributes, size volume, value value, now to a backpack with a capacity of W, ask the most can take away how much value of the goods.int f[w+1]; // F[x] Indicates the maximum value when the backpack capacity is X for (int i=0; i) for (int j=w; j>=size[i]; j--) // ReverseFull backpackIf the item does not count as many items as the

The backpack was too superficial to understand, recently looked again, and recorded the understanding of the experience:Reference: http://www.cppblog.com/tanky-woo/archive/2010/07/31/121803.html01 BackpackState transfer: F[i][j] = Max{f[i][j], F[i-1][j-v[i]]+w[i]} key is to take or not take, dual for loop, all starting from 0One-dimensional array: f[j] = Max{f[j], F[j-v[i]] + w[i]}, where the inner loop is the volume is reversed, this must be well und

2214 knapsack problemAccept:6 Submit:9Time limit:3000 mSec Memory limit:32768 KB problem DescriptionGiven a set of n items, each with a weight w[i] and a value v[i], determine a-to-choose the items into a knapsack so T Hat The total weight are less than or equal to a given limit B and the total value is as large as possible. Find the maximum total value. (Note that each item can is only chosen once).InputThe first line contains the integer T indicating to the number of test cases.For each test c