js backpack

Link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 2159 The first two-dimensional cost backpack, I still feel very tricky. Later I looked at the materials and added one dimension to the one-dimensional model, which is actually composed of two 001 backpacks. For more information, see: The two-dimensional bag problem refers to: for each item, there are two different charges; the two costs must be paid at the same time when this item is selected; t

definition of Backpack: A backpack is a collection data type that does not support removing elements from it-the purpose of which is to help collect elements with columns and iterate through all the collected elements (columns can also check if the backpack is empty or get the number of elements in the backpack). The o

I've come to the water blog again.Packet backpack is a kind of deformation of LC (01) Backpack. The items in the packet pack are divided into groups, and only one item in each group can be picked up and added to the backpack, which is the difference from the 01 backpack.In the 01 backpack, we use each item as a dynamic

Question: n represents the total number of classes, and m represents the number of days.The following is a matrix of n * m: The j-th value of line I represents the j-day benefit of section I .. If it takes no more than m to attend classes, how can we get the greatest benefit!Contact 01 backpack. The difference is that each class can only last once at most !! That is, the items in each row in the matrix are either taken or not taken !! This is a groupi

} the } +printf"%d\n", ans); - } $ return 0; $}View CodeTest instructions: Each line gives Si and fi, representing two properties of the cow, and then asked to select a few cows, yes, the sum of the total S and Total F, note s and F are not negativeidea: It is obvious that the problem is taken and not taken, the first idea of this kind of problem is the backpack, but this topic is obviously different from the general

Topic ConnectionBackpack Nine talk----full backpackThere are n items and a backpack with a capacity of V, with unlimited pieces available for each item. the cost of item I is C[i] and the value is w[i]. The solution of which items are loaded into the backpack allows the sum of the costs of these items to be no more than the backpack capacity and the maximum valu

Original title Link: click hereProblem Solving Ideas:Multi-knapsack problem, not very understanding, understand the supplementary.The idea of an online blog is:for each coin: IF value x number >=m then the number of times to take this coin is equal to unlimited, can be considered as a complete backpack ELSE then consider 0-1 backpack (binary optimization), is to combine the V and num of this

Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=1059Test instructions: There are six marbles worth 1 to 6, each of which is given the amount of marbles. Determine whether the marbles can be divided into two parts to make them equal in value.Converted to multiple knapsack problems. The cost of the item equals the value of the item, and the backpack capacity is half the total cost. Multi-backpack run ag

Bone Collectorproblem descriptionmany years ago, in Teddy ' s hometown there were a man who was called "Bone Collector". Collect varies of bones, such as dog ' s, cow ' s, also he went to the grave ...The bone collector had a big bag with a volume of V, and along he trip of collecting there is a lot of bones, obviously , different bone have different value and different volume, now given the each bone's value along his trips, can you CALCU Late out the maximum of the total value the bone collect

first-class priority. It is assumed that there is no time conflict between courses.Enter a descriptionInput DescriptionThe first line of the input file consists of two integers N, M (in the middle separated by a space) where 1≤n≤300,1≤m≤n.The following n lines represent one course per line. The class number is 1,2,...,n in turn. Each line has two numbers (separated by a space), the first number is the class number of the course first (if there is no first course, the item is 0), the second numb

This problem at first glance is a common 01 backpack, the most basic, but carefully look at the data, found that the ordinary can not do, carefully observed array found n relatively small, using this feature will be divided into the first half and the second half of this good, at that time in the Internet to find the problem, not found, and later in the Challenge program design found this question Just take a quote.The method of selecting items always

01 Backpack (Zeroonepack): there are n items and a backpack with a capacity of V. (Only one piece per item) The cost of item I is c[i] and the value is w[i]. The sum of the values is maximized by solving which items are loaded into the backpack. This is the most basic knapsack problem, characterized by: only one piece of each item, you can choose to put or not pu

These two questions are the basic problem of multiple backpacks, the front of the anchor test instructions is: give the value of each object and the number of objects, how to divide so that the value of a A, the value of a can not be less than B, similar to the Nyoj on the stamp of your half that meaning, but here is not one but many, So multiple backpacksThe previous question is to use half of the sum as the capacity of the backpack to ask, the code