ralink 3070

The bare question, the simplest FIB application template, is a new skill get.In fact, and the fast power is almost, but the matrix instead of the recursive type.1#include 2#include 3#include 4 using namespacestd;5 Const intMAXN =1005;6 structnode7 {8 inta[2][2];9 voidInit ()Ten { Onea[0][0] = a[1][0] = a[0][1] =1; Aa[1][1] =0; - } - }; the node Mul (node A,node b) - { - node C; - for(inti =0;i2; ++i) for(intj =0;j2;++j) + { -C.A[I][J] =0; + for(intK =0;k2; ++k)

2006To give you a formula to solve the Fibonacci sequence. Q: Given a number n, you use this formula to calculate the last four bits of f (n).Idea-The topic has already told us to use the matrix multiplication to seek Fibonacci number, the question is n is very big, if the direct matrix multiply n-1 times, certainly tle. So we can use two points to find a fast power:Complexity analysis--time complexity: O (n), spatial complexity: O (1)Attach the AC code:#include Copyright NOTICE: This article

; b[2][2]=0; while (n) { if (n1) { memset (kk,0,sizeof (KK)), for (i=1;i { for (j=1;j { for (k=1;k { kk[i][j]= (kk[i][j]+a[i][k]*b[k][j])%mod; } } } for (i=1;i { for (j=1;j { A[i][j]=kk[i][j]; } } n--; } N=n/2; Memset (kk,0,sizeof (KK)); for (i=1;i { for (j=1;j { for (k=1;k { kk[i][j]= (kk[i][j]+ B[I][K]*B[K][J])%mod; } } } for (i=1;i { for (j=1;j { B[i][j]=kk[i][j]; } } } return a[1][2]; } int main (void){__int64 I,j,k,k1,k2,n;while (scanf ("%i64d", n) ==1){if (N==-1) return 0;if (n

Fibonacci Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 10931 Accepted: 7770 DescriptionIn the Fibonacci integer sequence, f0 = 0, f1 = 1, and fn = fn ? 1 + Fn ? 2 for n ≥2. For example, the first ten terms of the Fibonacci sequence is:0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ...An alternative formula for the Fibonacci sequence is.Given an integer n, your goal was to compute the last 4 digits of Fn.InputThe input test file woul

#include Matrix Quick Power POJ 3070

#include 7 using namespacestd;8 Const intMod=10000;9 Ten intN; One structMatrix A { - intan[2][2]; - }res; the matrix Multiply (matrix A,matrix b) - { - matrix S; -memset (s.an,0,sizeof(s.an)); + for(intI=0;i2; i++) - { + for(intj=0;j2; j + +) A { at for(intk=0;k2; k++) - { -S.AN[I][J] + = a.an[i][k]*B.an[k][j]; - if(S.an[i][j]>mod) s.an[i][j]%=MoD; - } - } in } - returns; to } + voidCalcintN) - {

/* Poj 3070 binary power + matrix multiplication note the Code's conciseness to write a function block separately */# include

Question: Calculate the nth entry of the Fibonacci series 1 #include "iostream" 2 #include "vector" 3 #include "cstring" 4 using namespace std; 5 6 typedef unsigned long int ULL; 7 typedef vector Poj 3070 Matrix Quick power Template

Fibonacci Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13728 Accepted: 9724 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = fn−1 + fn−2 for n≥2. For example, the first ten terms of the Fibonacci sequence is: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... An alternative formula for the Fibonacci sequence is . Given an integer n, your goal was to compute the last 4 digits of Fn. Input The input test file would contain

Recently I bought a high-power wireless network card with a chip of ralink3070, Which is used normally in Windows, but the speed in Ubuntu is always very unstable and cannot be accessed well. It is a problem with the driver, so you are prepared to

Rapid matrix power 1 while(N)2 {3     if(N&1)4     res=res*A;5     n>>=1;6     A=A*A;7 }   1 #include 2 using namespace std; 3 #deinfe mod 10000 4 struct matrix 5 { 6 int m[2][2]; 7 }ans,base; 8 matrix multi(matrix a, matrix b) 9 {

The meaning is to use matrix multiplication to find the last four digits of the nth of the Fibonacci series. If the last four digits are all 0, the output is 0. Otherwise Remove the leading 0 from the last four digits of the output... ... Yes... ...

/* Very watery matrix question, nothing to say... */# include # include # include using namespace STD; struct matrix {long a [3] [3];} A, B; matrix mult2 (matrix A, matrix B) {// matrix multiplication matrix C; For (INT I = 1; I

Evaluate the nth entry (0 ≤ n ≤ 1,000,000,000) of the Fibonacci series, and evaluate the result after m modulo Solution: Solve the nth item directly. Because n is too large, the time complexity is very high. We need to construct a matrix that is

It is the matrix algorithm of Fibonacci, but the addition is because the number is large, so we need to take the 10000 modulo, And the modulo can be used to calculate the matrix. The data in this question is not strong, but the value is limited to

Question: known f0 =0, F1 = 1, and Fn = FN−1 + FN−2 for n ≥2. FN % 10000. The rapid power of the matrix is used here. In the final analysis, the Rapid power is to split K in a ^ K into a binary system. For example: 5 ^ 5 = 5 ^ (1*1 + 0*2 + 1*4) = 5 ^

Fibonacci Time limit:1000 ms   Memory limit:65536 K Total submissions:6946   Accepted:4908 Description In the Fibonacci integer sequence,F0 = 0,F1 = 1, andFN=FN− 1 +FN−2N≥2. For example, the first ten termsThe

generates diagnostics : Ralink/kconfig:206:warning: ' Rt_first_card ': number is invalid ralink/kconfig:207:warning: ' Rt_first_card ': Number is invalid ralink/kconfig:208:warning: ' Rt_first_card ': number is invalid ralink/kconfig:221:warning: ' Rt_second_card ': number is invalid

Transplantation of rt3070 on the S3C2440 Platform 1. Download the original driver from the official websiteHttp://www.ralinktech.com/en/04_support/license.php? Sn = 5016 Then put the driver code in the/home/Tango/code/linux-2.6.32.2/Drivers/NET/wireless/directoryThe/home/Tango/code/linux-2.6.32.2 is the linux2.6.32.2 kernel source code path. 2. Modify the MAKEFILE file in the rt3070 driver root directory2. 1. Define the chip type and header file path and select the hardware operating platform Ch

Android4.2 debug the RT3070 WiFi Module After four days, I finally learned something. Let's summarize it today.Monday 1. Test the WiFi module on PC ubuntu Two results are obtained. ubuntu12.10 is the driver that supports this WiFi module, such as rt2x00usb and rt2x00lib. The product id is 148f: 3070. It also brings some confusion. How can there be so many modules? Rtl8192cu is a module. What should I do on Android? I learned that the drivers of stand