Do not perform the remove/add operation of elements in the Foreach loop. The remove element uses the Iterator method, which requires a lock on the Iterator object if the concurrency operation.
Positive example: iterator
while (Iterator.hasnext ()) {
String item = Iterator.next ();
If (delete element's condition) {
Iterator.remove ();
}
}
Counter example:
Successful}//delete the I data element of L and return its value with E//Note that this is *e, not E, which is different from the variable e in the insert.Status List_link_delete (linklist *l,intI, Elemtype *D) { intj=1; Linklist p, q; P= *L; while(P->nextj//Traverse to find the first element of I{p= p->Next; ++J; } if(! (P->next) | | J >i)returnERROR;//The first
1. Linked list Remove duplicates from Sorted ListGiven a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3.Ideas:There are generally two ways to implement a linked list
Remove duplicate items from an unordered linked list, sort and remove
Problem
Remove duplicate items from an unordered linked list?
Appendix,
If temporary cache is not allowed, how can you solve this problem?
Analysis
If you can use extra storage space, we will open an array
Leetcode 2. Remove duplicate elements from the ordered linked list and array Remove Duplicates, leetcodeduplicates1. linked List, so that duplicate elements only appear once Remove Duplicates from Sorted List
Given a sorted linked
Pop_back ();// Delete The last linked list element of list3) iteratorerase (iterator POS);// Delete The linked list element that Pos points to4) Iteratorerase (iterator first, iterator last);// Delete all linked list elements pointed to by the iterator interval [First, la
LeetCode 19 Remove Nth Node From End of List Remove the Nth Node, leetcodenth
Question:
Given a linked list, remove the nth node from the end of list and return its head.
For example,
Given linked
1. ConceptThe previous blog post we talked about the list, where a method remove () is a temporary comment, this method is a bit complicated, you need to add a previous () method to find the element to delete the previous node, this blog post we analyze the Remove () method.When you delete a node from a linked
Given A linked list, remove the nth node from the end of the list and return its head.For example, n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5.Note:Given n would always be valid.Try to do the in one pass.Linked list of a simple
Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode027. Remove Element (Easy) link :Title: https://oj.leetcode.com/problems/remove-element/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions :Deletes all numbers in
"203-remove Linked list Elements (remove elements from single-linked list)""leetcode-Interview algorithm classic-java Implementation" "All topics Directory Index"code Download "Https://github.com/Wang-Jun-Chao"Original QuestionRemove all elements from a linked list of intege
Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode 027. Remove Element (Easy) link :
Title: https://oj.leetcode.com/problems/remove-element/Code (GitHub): Https://github.com/illuz/leetcode :
Deletes all numbers in an array
Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 .Idea: This problem is similar to the previous one, the concrete solution is as follows:/** * Definition for singly-linked list. * public class ListNode {* int val; * ListNode Next; * l
Total accepted:90247 Total submissions:254602 difficulty:easy Given a sorted linked list, delete all duplicates such this each element appear only once.For example,Given 1->1->2 , return 1->2 .Given 1->1->2->3->3 , return 1->2->3 ./** Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * ListNode (int x) : Val (x), Next (NULL) {}};
Total accepted:43183 Total submissions:160460 difficulty:easy Remove all elements from a linked list of integers, that has value val.ExampleGiven: 1---2--and 6---3---4---5, val = 6Return: 1--2--and 3--4--5(e) Remove Element (e) Delete Node in a Linked List/** Definition for
Remove Duplicates from Sorted ListGiven a sorted linked list, delete all duplicates such this each element appear only once.For example,Given1->1->2, return1->2.Given1->1->2->3->3, return1->2->3.Main topic:Remove the same elements within an ordered list, that is, the same element
', ' Beidou dan Yuan-june ' star ', ' Beidou Polar Star June ', ' Beidou day close Broken Army star June ']print ( Newmember.count (' Beidou Day close the Army star June ') "#扩充为原来的三倍newmember *=3print (newmember.count (' Beidou Day Guan June)")Result——————————————————————————————————————————The essence of the blog, in the technical part, more in the town yard a Poem. Python version 3.5, system Windows7.Python
Leetcode Topic Description:Remove all elements from a linked list of integers, that has value val.ExampleGiven: 1---2--and 6---3---4---5, val = 6Return: 1--2--and 3--4--5Generate linked ListIf the input element is not 0, it is added to the tail of the list, if 0, does not join, and the resulting list work is completed.
Test instructions: Removes all elements in the linked list that have an element value of Val.Idea: The algorithm complexity is definitely O (n), then the pursuit of less code and less additional operations. I can't do it.1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * ListNode *next;6 * ListNode (int x): Val (x), Next (NULL) {}7 *
Total accepted:59433 Total submissions:230628 difficulty:medium Given a sorted linked list, delete all nodes that has duplicate numbers, leaving only distinct numbers from the Original list.For example,Given 1->2->3->3->4->4->5 , return 1->2->5 .Given 1->1->1->2->3 , return 2->3 ./** Definition for singly-linked list. * struct ListNode {* int val; * ListNode *next; * ListNode (int x) : Val (x), Next (NULL)
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