rsa algorithm source code

STL source code profiling algorithm stl_heap.h Heap------------------------------------------------------------------------- Binary heap is a Complete binary Tree. Implicit representation: tree is expressed in array. Tip: Keep the #0 element of array, and the left and right subnodes of element I are 2i and 2i + 1, respectively, The parent node is I/2 --> STL do

(in selectmodel) (4) When splitting nodes for discrete values, the number of instances in the bag that exceed one is smaller than minnoobj (in spliter) (5) When the continuous value is split and calculated, the number of valid instances is less than 2 * minnoobj (in spliter) There are four stop conditions for reptree (1) The number of training sets is less than 2 * minnum (2) If the enumerated type is (3) If the value is of the numerical type, the variance is smaller than a given value. (4) rea

This is a creation in Article, where the information may have evolved or changed. The Strings.go package implements a Rabin-karp algorithm. A bit of a meaning. About this algorithm:Turing community has an article: illustrated Rabin-karp string Lookup algorithmAbout Go Source implementation:Netizen Golove has written a very detailed explanation. Http://www.cnblogs.com/golove/p/3234673.html Golove that has be

cigar diagram of the rotation. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%rotated cigar x from [-5 5]% x=-7:0.01:7;% [X,y]=meshgrid (x);% for I=1:size (x,1)% for J=1:size (y,1)% p=[x (i,j), Y (i,j)] ';% x (i,j) =m (1,:) *p;% y (i,j) =m (2,:) *p;% end% end% z=x.^2+ (10^4) *y.^2;% axis ([ -7,7 , -7,7]);% MESHC (x, y, z);%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% drawing ellipse. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%ellipse x from [ -5-5]% x=-5:0.01:5;% [X,y]=meshgrid (x);% z=x.^2+10.^4* (y.^2);% Axis ([ -5,

This article Senlie the original. Reprint please keep this address:Http://blog.csdn.net/zhengsenlieHeap-------------------------------------------------------------------------Binary heap is a completely binary tree.Implicit notation: The tree is expressed as an array.Tip: Keep the #0 elements of the array. Then the left and right child nodes of element I are 2i and 2i + 1 each,The parent node is I/2---and the STL doesn't use such a small trickArray cannot be dynamically resized, so vector is su

This article is senlie original, reproduced Please retain this address: http://blog.csdn.net/zhengsenlie Partial_sort/partial_sort_copy Certificate ----------------------------------------------------------------------------------------------------------------------------------------- Description: This algorithm accepts a middle iterator (in the column of the sequence [first, last) and reschedules [first, last ), Sort the Middle-first smallest element

cluster centers generated by the two outer iterations is equal, that is, the cluster center is not split, (3) maximum number of clusters There are two exit conditions for the inner iteration: (1) the clustering centers allocated by all use cases in the two inner iterations are the same (2) the maximum number of iterations is reached. 3. How to Determine the cluster center A: The arithmetic mean of all attributes is the cluster center. 4. Is there any trick used to improve efficiency in the impl

This article Senlie original, reproduced please retain this address:Http://blog.csdn.net/zhengsenlieIncludes (applied to ordered interval)-------------------------------------------------------------Descriptive narrative: Both S1 and S2 must be orderly sets. Infer whether the sequence two S2 "covers" the sequence one S1, that is, whether each element of S2 appears in S1 "Ideas:1. Traverse two intervals. Until one of them is finished.2. Assume that the element of sequence two is less than the ele

Help a friend to do, as if is a face question. Suppose, however, that the investigation is recursive. Should be enough, the robustness of the program and versatility are very general said ...#include a[count++] = n; } else { a[count++] = n; Myrevert (N/10, a);} } int main () { int n; int a[1000]; scanf ("%d", n); Myrevert (n, a); for (int j = 0; J "Source code"

This article Senlie original, reproduced please retain this address:Http://blog.csdn.net/zhengsenliePre_permutation----------------------------------------------------------------Descriptive narrative: The previous permutation of the sequence marked by [first, last].Assume no, return false, have, return trueIdeas:From the back forward1. Find two adjacent elements, so that the left side of the element is *i, the right side of the element is *ii, and meet *i > *ii2. Find the first element that is

STL source code profiling algorithm stl_algo.h -- pre_permutation Pre_permutation---------------------------------------------------------------- Description: gets the first permutation and combination of the sequence marked by [first, last. If no value exists, false is returned. If yes, true is returned. Ideas: From the back to the front 1. Find two adjacent el

This article is Senlie original. Reprint please keep this address:Http://blog.csdn.net/zhengsenlieInplace_merge (applied to ordered interval)--------------------------------------------------------------------Descriptive narrative: Suppose that two connected sequences [first, middle] and [middle, last] are sorted,Then Inplace_merge can combine them into a single sequence and remain in order.Source:Template Demo Sample:int main () { int a[] = {1, 3, 5, 7, 2, 4, 6, 8}; Inplace_merge (A, A + 4, a

#include using namespacestd;intMain () {intA= -, b=3, winner=0;//Total number A, number to B in multiples of left, last man winner for(intI=2; i) Winner= (winner+b)%i; cout"Winner:"1Endl;}We consider the following process1 2 3 4 5 6 ..... K-1 k k+1 ... n-1 nThe first number for the K-brother hangs, and then the rest of the n-1 individuals, from the k+1 continue.K+1 k+1 .... n-1 N 1 2 3 4 5 6,The sequence numbers are all minus k, resulting in the following sequences:1 2 3 4 5 6 ..... N-1That

Introduction: TreeMap and TreeSet are two important members of the Java Collection Framework, where TreeMap is a common implementation class for the Map interface, and TreeSet is a common implementation class for Set interfaces. Although the interface specification implemented by HASHMAP and HashSet is different, the TreeSet is implemented through TREEMAP, so they are implemented exactly the same way. and the implementation of TREEMAP is the red-black tree a