trapping for beginners

E: # small SunPrint ("Error:%s"% e)Print ("Hello, World")Fourth usage: try...except...finallyTryPrint (a)Except Indexerror as E: # small SunPrint ("Error:%s"% e)Finally: #无论是否能捕捉到错误, the program after finally runsPrint ("Hello, World")# Uses: Generally we use in file or database resources processingTryFile = open (' Test.txt ', ' W ')File.read ()Except Exception as E:Print ("Error:%s"% e)FinallyFile.close ()Fifth usage: Try...except...elseTryA = 4BExcept Exception as E:Print ("Error:%s"% e)Else

#-*-Coding:utf8-*-‘‘‘__author__ = ' [email protected] '42:trapping Rain Waterhttps://oj.leetcode.com/problems/trapping-rain-water/Given n non-negative integers representing an elevation map where the width of each bar is 1,Compute how much water it was able to trap after raining.For example,Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.===comments by dabay===Please refer to: http://blog.csdn.net/wzy_1988/articl

Title Link: Trapping Rain waterGiven n non-negative integers representing an elevation map where the width of each bar are 1, compute how much water it is able to trap after raining.For example,Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. ^ 3| ■ □: water 2| ■ □ □ □ ■ ■ □ ■ ■: elevation map 1| ■ □ ■ ■ □ ■ ■ ■ ■ ■ ■ The requirement of this problem is to calculate how much water can be loaded. Where the number in the arra

Given m x n a matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the VO Lume of water it is able to trap after raining.Note:Both m and N is less than 110. The height of each unit cell is greater than 0 and was less than 20,000.Example:Given the following 3x6 height map:[ [1,4,3,1,3,2], [3,2,1,3,2,4], [2,3,3,2,3,1]]return 4.The above image represents the elevation map [[1,4,3,1,3,2],[3,2,1,3,2,4],[2,3,3,2,3,1]] before the rain.After the rain, w

"Title description"Given n x m non-negative integers representing an elevation map 2d where the area of each cell is 11, compute how much water it's able to trap after raining.Given n x m nonnegative integers, which represent two-dimensional elevation maps, the area of each unit is 1 x 1, calculating how much water can be caught after the rain."Topic link"www.lintcode.com/en/problem/trapping-rain-water-ii/"Problem Analysis"First we should be able to a

Given n non-negative integers representing an elevation map where the width of each bar are 1, compute how much WA ter It is the able to trap after raining.For example,Given [0,1,0,2,1,0,1,3,2,1,2,1] , return 6 .The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of the Rain Water (blue section) is being trapped. Thanks Marcos for contributing this image!Analysis:We scan the whole array twice. First:from head to end; Second:from end to start.In every

Title Link: trapping-rain-waterImport java.util.stack;/** * Given n non-negative integers representing an elevation map where the width of each bar is 1, Compute how much water it was able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.The above elevation map are represented by array [0,1,0,2,1,0,1,3,2, 1,2,1]. 6 units of rain Water (blue section) is being trapped. Thanks Marcos for contributing this image! * */public cl

Feeling andContainer with most waterVery much like, here is a question, if let the ball biggest pit, how to do?and candy the problem, it seems that the double sweep seriesRef http://fisherlei.blogspot.com/2013/01/leetcode-trapping-rain-water.html Double Sweep Public classSolution { Public intTrapint[] A) {if(a==NULL|| A.LENGTHreturn0; intres=0, curv = 0, max=a[0]; int[] ML =New int[A.length]; int[] MR =New int[A.length]; for(intI=1; i) {Ml[i]=Max; Ma

https://oj.leetcode.com/problems/trapping-rain-water/This problem uses the monotone queue to be able to solve the O (n) time. Maintains a sort of monotone queue in descending order. If Ai>a[que.front] means that you can use Que.front as the top to calculate the water once.When starting from 0-n, be aware that there are elements in the queue. A monotone queue needs to be executed in reverse. But just go to the front location of the previous queue.class

Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar are 1, compute how much water it is able to trap after raining.For example,Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of the Rain Water (blue section) is being trapped. Thanks Marcos for contributing this image!Idea: This question is simple to see, but

Source of the topic:https://leetcode.com/problems/trapping-rain-water/ Test Instructions Analysis:Enter a set of arrays representing a height map with a width of 1. Q, how much water can this map collect after the rain? For example, enter an array [0,1,0,2,1,0,1,3,2,1,2,1] and return 6.: Topic Ideas:Although this topic is hard difficulty, but it is not very difficult. It is not difficult to find that the water is from the highest number an

Topic:Given n * m non-negative integers representing an elevation map 2d where the area of each cell was 1 * 1, compute how much Water it is able to trap after raining.Ideas:This problem is an extension of the previous question, http://www.cnblogs.com/AndyJee/p/4821590.htmlThe previous given is a one-dimensional array, and here is a two-dimensional array, the image of understanding, is to provide a three-dimensional cylindrical container, to find the maximum size of the container can accommodate

Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar are 1, compute how much WA ter It is the able to trap after raining.For example,Given [0,1,0,2,1,0,1,3,2,1,2,1] , return 6 .The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1].In this case, 6 units of the Rain Water (blue section) is being trapped. Thanks Marcos for contributing this image!Idea: Find the maximum value and it

Given n non-negative integers representing an elevation map where the width of each bar are 1, compute how much WA ter It is the able to trap after raining.For example,Given [0,1,0,2,1,0,1,3,2,1,2,1] , return 6 .The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1].In this case, 6 units of the Rain Water (blue section) is being trapped. Thanks Marcos for contributing this image!Title: Given n non-negative integers represent a width chart, the width of each small lattice is 1,

Leetcode dynamic planning Trapping Rain Water, leetcodetrapping This article is senlie original, reproduced Please retain this address: http://blog.csdn.net/zhengsenlie Trapping Rain Water Total Accepted: 14568 Total Submissions: 50810My Submissions Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For exa

LeetCode --- 42. Trapping Rain Water Link: Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. ^ 3| ■ □: water 2| ■ □ □ □ ■ ■ □ ■ ■: elevation map 1| ■ □ ■ ■ □ ■ ■ ■ ■ ■ ■ ————————————————————————>The

Given m x n a matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the VO Lume of water it is able to trap after raining.Note:Both m and N is less than 110. The height of each unit cell is greater than 0 and was less than 20,000.Example:Given The following 3x6 height map:[ [1,4,3,1,3,2], [3,2,1,3,2,4], [ 2,3,3,2,3,14.The above image represents the elevation map [[1,4,3,1,3,2],[3,2,1,3,2,4],[2,3,3,2,3,1]] before the rain.After the rain, water is

https://leetcode.com/problems/trapping-rain-water/Idea One: refer to 84. Largest Rectangle in histogram, with stack as auxiliary Public classSolution { Public intTrapint[] Heights) { intresult = 0; StackNewStack(); for(inti = 0; i ) { while(!stack.isempty () Heights[stack.peek ()] Heights[i]) { intTMP = Stack.pop ();//Index of Bottom intHeight = Stack.isempty ()? 0:math.min (Heights[stack.peek ()], he

When writing code, the most afraid of code to write hundreds of thousands of lines, but a running program crashes, in order to improve the robustness of the Code, the following provides a way to improve the robustness of the code:　　Exception trapping mechanism1 // exception capture mechanism: Improve code robustness 2 @try---@catch---@finally The following is a small demo of a printed array to illustrate its usage1Nsarray *arr = @[@Ten, @ -, @ -];2

Describe Given n non-negative integers representing an elevation map where the width of each bar is 1, computehow much wat Er it is able-trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. Analysis: For each pillar, find the tallest pillar on the left and right side, the area that the pillar can hold is min (max_left,max_right)-height. So1. Scan from left to right, and for each pillar, the left maximum value is obtained;2. Scan from