1226 water pouring problem, 1226 water pouring Problem
1226 water pouring Problems
Time Limit: 1 s space limit: 128000 KB title level: Gold Title Description
Description
Two flags without scale are available for both x and y litre (x and y are integers and are not greater than 100. There is also a water tank, which can be used to fill the water bottle or take the water poured out from the water bottle. The water can also be dumped between the two water bottles. It is known that x is an empty pot, and y is an empty pot. Ask how to pour water or fill water, and use the minimum number of steps to generate a z (z ≤ 100) litre of water in the x or y litre pot.
Input description
Input Description
One row, three data records, x, y, and z;
Output description
Output Description
A row outputs the minimum number of steps. If the target cannot be reached, the output is "impossible"
Sample Input
Sample Input
3 22 1
Sample output
Sample Output
14
Data range and prompt
Data Size & HintCATEGORY tag
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This question, is indeed done by me...
First, the question is too disgusting... There are eight situations... At the beginning, I only considered four types ....
Then, when recording the number of steps, step 2 is the correct answer...
The face of AC is awesome .....
1 # include <iostream> 2 # include <cstdio> 3 # include <queue> 4 # include <cstdlib> 5 using namespace std; 6 const int MAXN = 1001; 7 int vis [MAXN] [MAXN]; 8 int x, y, z; 9 int step = 0; 10 int p1, p2; 11 void bfs () 12 {13 queue <int> qx; queue <int> qy; 14 qx. push (x); qy. push (y); 15 while (qx. size ()! = 0 & qy. size ()! = 0) 16 {17 int wx = qx. front (); int wy = qy. front (); 18 if (wx = z | wy = z) 19 {printf ("% d", step/2); exit (0 );} 20 qx. pop (); 21 qy. pop (); 22 if (wx <0 | wy <0 | wx> x | wy> y | vis [wx] [wy] = 1) continue; 23 vis [wx] [wy] = 1; 24 step ++; 25 qx. push (x); qy. push (wy); // x filled with 26 qx. push (0); qy. push (wy); // empty x 27 qx. push (wx); qy. push (y); // y filled with 28 qx. push (wx); qy. push (0); // empty y 29 qx. push (0); qy. push (wy + wx); // x-> y no shenyu30 qx. push (wx-y + wy); qy. push (y); // you shengyu31 qx. push (wx + wy); qy. push (0); // y-> x noshengyu32 qx. push (x); qy. push (wy-x + wx); // youshengyu... 33} 34} 35 int main () 36 {37 scanf ("% d", & x, & y, & z); 38 bfs (); 39 printf ("impossible"); 40 return 0; 41}