165. Compare Version Numbers Leetcode Python

Compare numbers version1 and Version2.
If Version1 > Version2 return 1, if Version1 < Version2 return-1, otherwise return 0.


Assume that the version strings is non-empty and contain only digits and the. Character.
The. Character does not represent a decimal point and was used to separate number sequences.
For instance, 2.5 are not "both and a half" or "half to version three", it is the fifth Second-level revision of the SEC Ond first-level revision.


Here are an example of version numbers ordering:


0.1 < 1.1 < 1.2 < 13.37
Credits:

Special thanks to @ts for adding this problem and creating all test cases.

This question is mainly about unequal lengths.

My practice is to add 0 to the front when the time is not equal.

Class solution:    # @param version1, a string    # @param version2, a string    # @return An integer    def compareve Rsion (self, Version1, version2):        num1=version1.split ('. ')        Num2=version2.split ('. ')        While Len (NUM1) or Len (num2):            If Len (NUM1) ==0:                num1=[0]            elif len (num2) ==0:                num2=[0]            else:                I1=int (num1[0])                i2=int (num2[0])                if i1<i2:                    return-1                elif i1>i2:                    return 1                Else:                    num1=num1[1:]                    num2=num2[1:]        return 0            

165. Compare Version Numbers leetcode Python