9-degree OJ 1062 piecewise functions (simulation)

9-degree OJ 1062 piecewise functions (simulation)

Question 1062: piecewise Functions

Time Limit: 1 second

Memory limit: 32 MB

Special question: No

Submit: 2877

Solution: 1671

Description:

Compile a program and calculate the value of the following piecewise Function y = f (x.
Y =-x + 2.5; 0 <= x <2
Y = 2-1.5 (X-3) (X-3); 2 <= x <4
Y = x/2-1.5; 4 <= x <6

Input:

A floating point number N

Output:

There may be multiple groups of test data. For each group of data,
Output the piecewise function value corresponding to N: f (N ). The result is retained with three decimal places.

Sample input:

1

Sample output:

1.500

#include
            
             #include
             
              #include
              
               double y(double x){    double result;    if(0<=x&&x<2.0)    {        result=-1*x+2.5;    }    else if(2<=x&&x<4){        result=2-1.5*(x-3.0)*(x-3.0);    }    else{        result=x/2-1.5;    }    return result;}int main(int argc, char *argv[]){    freopen("1062.in", "r", stdin);    double N;    while(~scanf("%lf",&N))    {        printf("%.3lf\n",y(N));    }    return 0;}