A case where the method closure parameter in Swift cannot omit parentheses

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We know that in swift, if the last parameter of the method is a closure type, you can omit the argument and follow the function directly behind it with a closure, such as:

func test(count:Int,(Int)->Bool){    //...}

You can call this:

test(11in    //...}

However, there are cases where parentheses cannot be omitted, such as in a For statement:

For dinosaurinchDinosaurs. Filter{(dinosaur), BoolinchDistancebetween (Tower. Spritecomponent. Node, Nodeb:dinosaur. Spritecomponent. Node) < Towertype. Range} {if let T = target{if dinosaur. Spritecomponent. Node. Position. x> t. Spritecomponent. Node. Position. x{target = dinosaur}} else{target = Dinosaur}}

The above statement will give an error, because after the for statement also with {},swift do not know which {}, like tongue twisters ...

You must surround {} with () behind the filter.

However, if you are not in the For statement, you can omit (), for example:

x = dinosaurs.filterin                distanceBetween(tower.spriteComponent.node, nodeB: dinosaur.spriteComponent.node) < towerType.range            }

A case where the method closure parameter in Swift cannot omit parentheses