Ask why the returned value cannot be obtained in the second method-php Tutorial

Why can't I get the return value in the following ways? This post is finally edited by u010416883 from 2013-06-011:37:22! Public & nbsp; static & nbsp; function & nbsp; query ($ SQL, & nbsp; $ unbuffered & nbsp; false) & nbsp ;{& nbsp; why can't I get the return value in the following ways?

This post was last edited by u010416883 at 11:37:22

Answer the following questions!

Public static function query ($ SQL, $ unbuffered = false ){
$ Ret = self ::$ db-> query ($ SQL, $ unbuffered); // when the sentence is successful, $ ret is 1 Note: self :: $ db-> query is mysql_query
If ($ unbuffered === true ){
$ Cmd = trim (strtoupper (substr ($ SQL, 0, strpos ($ SQL ,''))));
If ($ cmd = 'select '){}
Elseif ($ cmd = 'update' | $ cmd = 'delete '){
$ Ret = self: $ db-> affected_rows ();
}
Elseif ($ cmd = 'insert '){
$ Ret = self: $ db-> insert_id (); // it indicates that the task is executed and the int type ID is returned.
}
}
Return $ ret; // The final return is not an int-type idnumber.
}

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What do you get?
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No matter whether there are any subsequent operations, at least $ ret = self: $ db-> query ($ SQL, $ unbuffered); is returned.
If yes, $ ret is 1 when the sentence is successful, and you say the return is null, it is obviously a query failure.
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Public function query ($ SQL, $ unbuffered = false) {...
Either query returns resources or query returns logical values.
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What is the SQL statement you run? What is $ unbuffered during query execution?
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You use elseif. if a condition breaks the following program, it will not go any more.