Binary conversion Issues in Java

Decimal turns into 16 binary:

integer.tohexstring (int i)

Decimal into octal

integer.tooctalstring (int i)

Decimal turns into binary

integer.tobinarystring (int i)

Hex turns into decimal

Integer.valueof ("FFFF", +). ToString ()

Octal into decimal

Integer.valueof ("876", 8). ToString ()

Binary goto Decimal

Integer.valueof ("0101", 2). ToString ()

Is there any way to directly convert the 2,8,16 into a 10-binary system?

Java.lang.Integer class

parseint (String s, int radix)

Resolves a string argument to a signed integer using the cardinality specified by the second argument.

Examples from JDK:
parseint ("0", ten) returns 0
parseint ("473", Ten) returns 473
parseint ("-0", returns 0)
parseint ("-ff", +) returns-255
parseint ("1100110", 2) returns 102
parseint ("2147483647", ten) returns 2147483647
parseint (" -2147483648", ten) returns-2147483648
parseint ("2147483648", ten) throws a NumberFormatException
parseint ("Kona", ten) throws a NumberFormatException
parseint ("Kona", returns 411787)

How the binary conversion is written (two, eight, 16) without algorithms

Integer.tobinarystring
Integer.tooctalstring
Integer.tohexstring

Arbitrary-binary conversions

Import Java.util.HashMap;  Import Java.util.Map;  Import Java.util.Stack; public class Hextransformatutil {/** * converts decimal to any binary value * @param the converted binary minimum bit, followed by a character value, such as 26 binary "Abcdefghi JKLMNOPQRSTUVWXYZ "* @param num Converts the decimal value * @param length to the specified string, if insufficient length length, automatically complements the minimum value, such as 26 binary" Abcdefghijklmno            PQRSTUVWXYZ "a" * @return */public static string Hex10toanly (string digths, int num,int length) {            StringBuffer str = new StringBuffer ("");          int base = Digths.trim (). Length ();          if (0==num) {str.append (Digths.charat (0));                }else{stack<character> s = new stack<character> ();                    while (num! = 0) {s.push (Digths.charat (num%base));                Num/=base;                } while (!s.isempty ()) {Str.append (S.pop ());          }} String prefix = "";          String suffix = str.tostring (); IF (Length>suffix.length ()) {for (int count = 0;count<length-suffix.length (); count++) {PR              Efix = prefix + digths.charat (0);        }} return prefix + suffix; /** * Convert any binary to a decimal value * @param digths the binary minimum bit before conversion, the character value that appears sequentially, such as 26 binary "ABCDEFGHIJKLMNOPQRSTUVWXYZ" *            @param hexvalue binary String value before conversion * @return */public static int HexAnlyTo10 (string digths, String hexvalue) { if (null==hexvalue| | "".          Equals (Hexvalue.trim ())) return 0;                    int base = Digths.trim (). Length ();          map<string,integer> Digthmap = new hashmap<string,integer> ();          int count=0;              for (char Item:digths.trim (). ToCharArray ()) {Digthmap.put ("" +item, Count);          count++;          } String str = new StringBuffer (Hexvalue.trim ()). Reverse (). toString ();          int sum = 0; for (int index = 0;index<str.length (); index++) {sum = nEW Double (Math.pow (base, Index)). Intvalue () * Digthmap.get ("" +str.charat (index)) +sum;      } return sum; } public static void Main (string[] args) {//Converts the decimal "0123456789" value 55 to 26 "ABCDEFGHIJKLMNOPQRSTUVWXYZ" pair                    The expected value does not require formatting of the last output string System.out.println (Hex10toanly ("abcdefghijklmnopqrstuvwxyz", 55, 0)); Converts the 26 binary "ABCDEFGHIJKLMNOPQRSTUVWXYZ" string value "CD" to the value corresponding to the decimal "0123456789" value 55, without having to format the last output string System.out.println (      HexAnlyTo10 ("abcdefghijklmnopqrstuvwxyz", "CD"));     }  }

　　

Binary conversion Issues in Java