C + + Fifth experiment--array separation

I. Questions and codes

 file name: array separation * AS By: Liu Jia Material * completion date: May 10, 2016 * Version number: v1.0 * Description of Task and solution Method section: Using Arrays and for language * Input Description: Enter 10 integers * problem description: Separate odd and even * program output: Even Group C is      : 2 4 6 8 0 Odd Group B is: 1 3 5 7 9* Problem analysis: Using array * Algorithm design: For statement if statement #include <iostream.h> void Main () {const int n=10;      int a[n],c[n],b[n],i,j=0,k=0;      cout<< "Please enter 10 number:" <<endl;          for (i=0;i<n;i++) {cin>>a[i];             if (a[i]%2==0) {c[j]=a[i];          j + +;              } else {b[k]=a[i];          k++;            }} cout<< "Even Group C is:"; for (j=0;j<n-k;j++) {cout<<c[j]<< "";         cout<<endl;            } cout<< "Odd Group B is:"; for (k=0;k<n-j;k++) {cout<<b[k]<< "";            cout<<endl; }    }  

Two. Running results

Three. Experience:

Actually not very will do this, fortunately, today the teacher explained a bit, on the copy down, a back on the write up, afraid to forget

Four. Summary of Knowledge points:

Utilize the FOR statement, if statement, to utilize the array

C + + Fifth experiment--array separation