[C + +] Reverse integer integer Flip __c++

Leetcode original title Link: https://leetcode.com/problems/reverse-integer/

Reverse digits of an integer.

EXAMPLE1:X = 123, return 321
example2:x = -123, return-321 brief analysis: This problem is not difficult, but to pay attention to a few points, such as negative flip or negative, to consider the overflow problem, there is no explanation, but according to the test results, when the data overflow, the return value is 0. Because of the possibility of data overflow, we can not simply use an integer to express this. It can be represented by a larger integer type, such as long, or by a string, which I use. This allows for a larger range of integers to be modified only by modifying some constants.

Implementation code:

Class Solution
{public
:
	int reverse (int x)
	{
		string sx = "";
		int flag = 1;
		if (x >= 0)
		{while
			(x!= 0)
			{
				sx = char (' 0 ' + x%) + SX;
				X/=}
		} else
		{
			flag =-1;
			while (x!= 0)
			{
				sx = char (' 0 '-x%) + SX;
				X/=}
		}
		string sr = "";
		for (int i = 0; i < sx.size (); i++)
		{
			sr = Sx[i] + sr;
		}
		if (Flag > 0 && strcompare (sr, "2147483647"))
		{return
			0;
		}
		if (Flag < 0 && Strcompare (sr, "2147483648"))
		{return
			0;
		}
		int ans = 0;
		for (int i = 0; i < sr.size (); i++)
		{
			ans = ans * ten + (Sr[i]-' 0 ');
		}
		return flag*ans;
	}

	BOOL Strcompare (string s1, string s2)
	{/
		*
		s1 >= S2 return true
		S1 < S2  return false
		*
		/ if (S1.size () > S2.size ()) return
			true;
		else if (s1.size () < S2.size ()) return
			false;
		
		return s1 > s2;
	}
;