/*
Keywords Search
Time limit:2000/1000 MS (java/others) Memory limit:131072/131072 K (java/others)
Total submission (s): 47794 Accepted Submission (s): 15228
Problem Description
In the modern time, Search engine came to the life of everybody like Google, Baidu, etc.
Wiskey also wants to bring the feature to his image retrieval system.
Every image has a long description, when users type some keywords to find the image, the system would match the keywords W ITH description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords would b E match.
Input
First line would contain one integer means how many cases would follow by.
Each case would contain integers n means the number of keywords and n keywords follow. (N <= 10000)
Each keyword would only contains characters ' a '-' Z ', and the length would be is not longer than 50.
The last line is the description, and the length would be a not longer than 1000000.
Output
Print How many keywords is contained in the description.
Sample Input
1
5
She
He
Say
Shr
Her
Yasherhs
Sample Output
3
*/
1#include <cstdio>2#include <cstring>3#include <iostream>4#include <algorithm>5 6 using namespacestd;7 8 Chars[Wuyi],m[1000001];9 intT,n,sz,ans;Ten inta[500001][ -]/*Dictionary Tree*/, q[500001],point[500001],danger[500001]/*Word End Flag*/; One BOOLmark[500001]; A - intins () - { the intnow=1, l=strlen (s); - for(intI=0; i<l;i++) - { - intt=s[i]-'a'+1; + if(A[now][t]) now=A[now][t]; - Elsenow=a[now][t]=++sz; + } Adanger[now]++; at } - - intAcmach () - { -q[0]=1;p oint[1]=0; - intnow,w=1, t=0; in while(t<W) - { tonow=q[t++]; + for(intI=1; i<= -; i++) - { the if(!a[now][i])Continue; * intk=Point[now]; $ while(!a[k][i]) k=Point[k];Panax Notoginsengpoint[a[now][i]]=A[k][i]; -q[w++]=A[now][i]; the } + } A } the + intSolve () - { $ intk=1, l=strlen (m); $ for(intI=0; i<l;i++) - { -mark[k]=1; the intt=m[i]-'a'+1; - while(!a[k][t]) k=Point[k];Wuyik=A[k][t]; the if(!Mark[k]) - for(intj=k;j;j=Point[j]) Wu { -ans+=Danger[j]; Aboutdanger[j]=0; $ } - } -printf"%d\n", ans); - } A + intMain () the { -scanf"%d",&T); $ while(t--) the { theans=0; thesz=1; thescanf"%d",&n); - for(intI=1; i<= -; i++) a[0][i]=1; in for(intI=0; i<n;i++) the { thescanf"%s", s); About ins (); the } thescanf"%s", M); the Acmach (); + solve (); - for(intI=1; i<=sz;i++) the {Bayipoint[i]=danger[i]=mark[i]=0; the for(intj=1; j<= -; j + +) thea[i][j]=0; - } - } the}
C + + Road set sail--ac Automaton (Keywords Search)