1. One-dimensional array names are passed as function parameters
An array name that corresponds to the address of the first element of the array;
Copy Code code as follows:
int a[10];
int *p;
P=a;
P=a and p=&a[0] are equivalent
Instance code:
Copy Code code as follows:
#include <iostream>
using namespace Std;
int main () {
int a[10]={1,2,3,4,5,6,7,8,9,10};
void Print (int *p, int n);
Print (a,10);
cout<<endl;
return 0;
}
void Print (int *p, int n) {
int i=0;
for (; i<n;i++) {
cout<<* (p+i) << "";
}
}
In the main function, the array name A is the value of the argument, that is, the value of &a[0] as the argument, and then in the print function, the pointer p to the INT variable is used to receive the passed value and to output the operation.
2. Multidimensional array names are passed as function parameters
In a two-dimensional array, array name A is a pointer to the first row a[0], meaning a=&a[0]; A[0] is a pointer to the first element a[0][0], that is to say a[0]=&a[0][0]
Instance code:
Copy Code code as follows:
#include <iostream>
using namespace Std;
int main () {
int a[3][4]={1,2,3,4,5,6,7,8,9,10,11,12};
void Print (int (*p) [4]);
Print (a);
cout<<endl;
return 0;
}
void Print (int (*p) [4]) {
int i=0,j=0;
for (i=0;i<3;i++) {
for (j=0;j<4;j++) {
cout<<* (* (p+i) +j) << "";
}
}
}
P is a pointer to a[0], then P+i is a pointer to A[i], * (p+i) is a pointer to a[i][0, then * (P+i) +j is a pointer to a[i][j], so * (* (p+i) +j) is the value of a[i][j]
