Math.Round (45.367,2) //Returns 45.37math.round (45.365, 2) // Returns 45.36
C # round () is not our Chinese understanding of rounding, is the foreigner's rounding, is in line with the IEEE standard rounding, specifically four six into, the following is in line with the Chinese understand the rounding
Math.Round (45.367,2, Midpointrounding.awayfromzero); // 45.37 Math.Round (45.365,2, Midpointrounding.awayfromzero) // Returns 45.37
Double Dvalue =95.12345;intIvalue =10000;stringstrvalue ="95.12345";stringresult =""; result= Convert.todouble (Dvalue). ToString ("0.00");//two digits after the decimal point, the result is 95.12result = Convert.todouble (ivalue). ToString ("0.00");//10000.00result = Convert.todouble (strvalue). ToString ("0.00");//95.12result= Convert.todouble (Dvalue). ToString ("P");//the percentage of 2 digits after the decimal point is obtained, and the% number is automatically added;//9512.35%result = Convert.todouble (strvalue). ToString ("f4");//retain 4 digits after the decimal point; //95.1235//One thing to note is that convert.todouble must be this double-precision, otherwise it will be an error.
C # decimal points reserved Two decimals, rounding function and use method