c 16 conversion into decimal: to right-to-left with the binary of each number is multiplied by 16 of the corresponding sub-party

#include <stdio.h>/* 16 binary into decimal: to multiply each number of binary from right to left by the corresponding sub-square of 16; in 16 binary: A (a) =10 B (b) =11 C (c) =12 D (d) =13 e (E) =14 f (f) = 15 Example: ce=12*16^1+14*16^0=192+14=206*/unsigned short int right (unsigned short int num, int n) {return (num<<n) | (Num>> (num)-n);} int main (void) {unsigned short  int  num = 0xfa;//up to 4 0xFABCD error unsigned short  int num2 = 0x2345;//short int Short integer 2 bytes total 2*8=16 of bits printf ("hexadecimal number you entered:% #x \ n", num);p rintf ("% #x十六进制数转换成十进制为:%d\n", Num,num);p rintf ("The hexadecimal number is bits:% D digit \ n ", sizeof (num) *8); return 0;}

　　

c 16 conversion into decimal: to right-to-left with the binary of each number is multiplied by 16 of the corresponding sub-party