C language Article editing implementation code

Problem:

Article editing

Function: Enter a page of text, the program can count the number of words, numbers, spaces.
Static storage of a page of articles, a maximum of 80 characters per line, a total of n rows; (1) The number of English letters and spaces and the total words of the whole article are counted; (2) count the number of occurrences of a string in the article and output the number of times, and (3) Delete a substring and move the following characters forward.
The storage structure uses the linear table, and uses several sub-functions respectively to realize the corresponding function;
Enter the form and range of the data: You can enter uppercase, lowercase letters, any numbers, and punctuation.
Output form: (1) Branch output user input of each line character; (2) 4 lines output "All letters", "Number of Numbers", "number of spaces", "Total Words" (3) output Delete a string after the article;

The code is as follows:

#include <stdio.h>
#include <stdlib.h>
#include "string.h"
#include <time.h>
#define MAXSIZE 256
Insert operation of linked list

void Insertelem (char *sqlist,int*len,int index,char elem) {
if (index> (*len) | | index<0) {
printf ("error!");
Exit (1);
}else {
for (int i=*len;i>=index;i--)
Sqlist[i+1]=sqlist[i];
Sqlist[index]=elem;
*len=*len+1;
}


}

Delete operation of linked list

void Deleteelem (char *sqlist,int*len,int index) {
if (index> (*len) | | index<0) {
printf ("error!");
Exit (1);
}else
{
for (int i=index;i<*len;i++)
SQLIST[I]=SQLIST[I+1];
*len=*len-1;
}
}

void Initsqlist (char *sqlist) {
int index=0;
while (index<maxsize) {
Char Ch=getchar ();
if (ch== ' # ') {
Sqlist[index]=ch;
break;}
Sqlist[index]=ch;
index++;
}
}
int Sum_a (Char*sqlist,int len) {
int in_len=0;
for (int i=0;i<len;i++) {
if (sqlist[i]>= ' A ' &&sqlist[i]<= ' Z ' | | Sqlist[i]>= ' a ' &&sqlist[i]<= ' Z ') {
in_len++;
}
}
return In_len;
}
int Sum_b (Char*sqlist,int len) {
int in_len=0;
for (int i=0;i<len;i++) {
if (sqlist[i]== ') {
in_len++;
}
}
return In_len;
}
int sum (char*sqlist) {
int in_len=0;
while (sqlist[in_len]!= ' # ') {
in_len++;
}
return In_len;
}
int Sum_c (Char*sqlist,int len) {
int in_len=0;
for (int i=0;i<len;i++) {
if (sqlist[i]!=10) {
in_len++;
}

}
return In_len;
}
void Print_a (char *sqlist,int len) {
for (int i=0;i<len;i++) {
printf ("%c", Sqlist[i]);
}
printf ("\ n");
}
void Print_b (char *sqlist,int len) {
printf ("The total number of letters:%d\n", Sum_a (Sqlist,len));
printf ("Total number of spaces:%d\n", Sum_b (Sqlist,len));
printf ("Total number of words:%d\n", Sum_c (Sqlist,len));
}

int Sun_char (char*sqlist,int len1,char* substr,int len2) {
int flag=0;
for (int i=0;i<len1;i++)
{
for (int j=0;j<len2;j++) {
if (Sqlist[i+j]!=substr[j])
Break
}
if (J==LEN2)
{
flag++;
}
}
return flag;
}

void Delete_sub_str (char *str, char *sub_str, int *len1,int *len2);
int main () {
Char Sqlist[maxsize];
printf ("Please enter the article you are writing to end with the character ' # '!") \ n ");
Initsqlist (sqlist);
int len=sum (sqlist);
printf ("you wrote the following: \ n");
Print_a (Sqlist,len);
Print_b (Sqlist,len);
Char Sub[maxsize];
Char Sub1[maxsize];
Go
printf ("Input 1 means query, input 2 means delete:");
int var=0;
scanf ("%d", &var);
Switch (VAR) {
Case 1:
printf ("Please enter the string you are looking for: \ n");
scanf ("%s", sub);
printf ("The number of strings you want to query in the article is as follows: \n%d\n", Sun_char (Sqlist,len,sub,strlen (sub));
Break
Case 2:
printf ("Please enter the string you want to delete \ n");
scanf ("%s", sub1);
int Len2=strlen (SUB1);
Delete_sub_str (SqList, Sub1, &len,&len2);
Break
}

printf ("Do you want to continue?" \ n Enter 1 to continue ");
scanf ("%d", &var);
if (var==1) {
Goto go;
}else
printf ("program operation finished!");
return 0;

}

void Delete_sub_str (char *str, char *sub_str, int *len1,int *len2)
{

int i,j,succ;
i=0;succ=0; /* Use the I-scan body t,succ to match the success flag */
while ((i<=*len1-*len2+1) && (!SUCC))
{
J=0;succ=1; /* with J-Scan mode p*/
while ((j<=*len2-1) &&SUCC)
if (Sub_str[j]==str[i+j]) j + +;
else succ=0;
i++;
}
if (SUCC)
{
For (j=0;j< (*len1-*len2-1); j + +)
{
STR[I-1]=STR[I+*LEN2-1];
i++;
}
*len1=*len1-*len2;
printf ("Delete results as follows: \ n");
for (i=0;i<*len1;i++)
{
printf ("%c", Str[i]);
}
printf ("\ n");
}
else printf ("\ n Error! There are no substrings to match the string! ");

}

C language Article editing implementation code