C Language Blog Job--function nested call

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First, the experimental work student performance management System Requirements 1.1 PTA topic 6-5 Recursive implementation sequential output integer

• Design ideas

  输入数字n调用函数 printdigits(n){定义变量res表示顺次输出的数字IF n/10=0res←n    递归出口否则调用函数printdigits(n-1)res←n%10输出res

• Code
  

• Debugging issues

  When the judgment condition is n=0, the result of entering a single number is wrong, instead n/10=0 can be

Second, this week's topic set PTA Final Ranking

Third, read the code to a certain number of steps there are several ways

#include <stdio.h>#include <stdlib.h>#include <string.h>static int step[128];static int m = 1;int count(unsigned int n);void cout(int n,int t);int main(){int a;    unsigned int n;    while(1){printf("请输入需要登上的台阶数量：");scanf("%d",&n);a = count(n);printf("登上%d个台阶共有%d种方法！分别如下：\n",n,a);cout(n,0);                m=1;    }system("pause");return 0;}int count(unsigned int n){    if(n == 1)        return 1 ;    if(n == 2)        return 2 ;    else         return count(n - 1) + count(n - 2) ;}void cout(int n,int t){    int i,j;    if(n<0)    return ;if(n == 0)    {printf("第%d种方法：",m);for(j=0;j<t;j++)            printf("%d ",step[j]);m++; printf("\n");    }    else    {for(i=1;i<=2;i++){step[t] = i;cout(n-i,t+1);}    }}

The function outputs the sum of all the sums of a number and sorts the digits of the number, and sets the static global variables before recursion to realize the condition that the recursive time-varying quantity does not reset. Iv. Summary of this week's study

• learned about recursive functions and macros with parameters
• You can set the number of pointers to hold pointer variables and set function pointers so that pointers point to functions
• Defines a pointer to a pointer to a level two pointer
• You can use the malloc () function to set up dynamic memory to avoid wasted space, freeing memory with the free () function

Learning experience

• There is still some misunderstanding about the engineering documents, not very understanding.

C Language Blog Job--function nested call