# C language calculation of bonus cases

Source: Internet
Author: User

The bonuses awarded by the Enterprise are based on the profit percentage. Profit (I) is less than or equal to 100,000 yuan, the bonus can be mentioned 10%, the profit is higher than 100,000 yuan, less than 200,000 yuan, less than 100,000 yuan part by 10% commission, higher than 100,000 yuan, Cocoa Commission 7.5%, 200,000 to 400,000, higher than 200,000 yuan of the portion, can commission 5% 400,000 to 600,000 when the portion of more than 400,000 yuan, can be a commission of 3%, 600,000 to 1 million when, higher than 600,000 yuan, can be a commission of 1.5%, more than 1 million yuan, more than 1 million yuan in the portion of 1% commission, from the keyboard input month profit I, the total number of bonuses should be issued?

1. Procedure analysis: Please use the axis to demarcation, positioning. Note that the definition needs to be defined as a growth integral type.

2. Program Source code:

`main() { long int i; int bonus1,bonus2,bonus4,bonus6,bonus10,bonus; scanf("%ld",&i); bonus1=100000*0.1;bonus2=bonus1+100000*0.75; bonus4=bonus2+200000*0.5; bonus6=bonus4+200000*0.3; bonus10=bonus6+400000*0.15; 　if(i<=100000) 　　bonus=i*0.1; 　else if(i<=200000) 　　　　　bonus=bonus1+(i-100000)*0.075; 　　　　else if(i<=400000) 　　　　　　　　bonus=bonus2+(i-200000)*0.05; 　　　　　　　else if(i<=600000) 　　　　　　　　　　　bonus=bonus4+(i-400000)*0.03; 　　　　　　　　　　else if(i<=1000000) 　　　　　　　　　　　　　　bonus=bonus6+(i-600000)*0.015; 　　　　　　　　　　　　　else 　　　　　　　　　　　　　　bonus=bonus10+(i-1000000)*0.01; printf("bonus=%d",bonus); }`

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