C language calculation of bonus cases

The bonuses awarded by the Enterprise are based on the profit percentage. Profit (I) is less than or equal to 100,000 yuan, the bonus can be mentioned 10%, the profit is higher than 100,000 yuan, less than 200,000 yuan, less than 100,000 yuan part by 10% commission, higher than 100,000 yuan, Cocoa Commission 7.5%, 200,000 to 400,000, higher than 200,000 yuan of the portion, can commission 5% 400,000 to 600,000 when the portion of more than 400,000 yuan, can be a commission of 3%, 600,000 to 1 million when, higher than 600,000 yuan, can be a commission of 1.5%, more than 1 million yuan, more than 1 million yuan in the portion of 1% commission, from the keyboard input month profit I, the total number of bonuses should be issued?

1. Procedure analysis: Please use the axis to demarcation, positioning. Note that the definition needs to be defined as a growth integral type.

2. Program Source code:

main()

{

long int i;

int bonus1,bonus2,bonus4,bonus6,bonus10,bonus;

scanf("%ld",&i);

bonus1=100000*0.1;bonus2=bonus1+100000*0.75;

bonus4=bonus2+200000*0.5;

bonus6=bonus4+200000*0.3;

bonus10=bonus6+400000*0.15;

　if(i<=100000)

　　bonus=i*0.1;

　else if(i<=200000)

　　　　　bonus=bonus1+(i-100000)*0.075;

　　　　else if(i<=400000)

　　　　　　　　bonus=bonus2+(i-200000)*0.05;

　　　　　　　else if(i<=600000)

　　　　　　　　　　　bonus=bonus4+(i-400000)*0.03;

　　　　　　　　　　else if(i<=1000000)

　　　　　　　　　　　　　　bonus=bonus6+(i-600000)*0.015;

　　　　　　　　　　　　　else

　　　　　　　　　　　　　　bonus=bonus10+(i-1000000)*0.01;

printf("bonus=%d",bonus);

}