C Language: Logical reasoning

1 A, B, C, D, e Five students are likely to participate in the computer contest, according to the following conditions to determine which (10 points)

Topic content:

A, B, C, D, e Five students are likely to participate in a computer contest, which is judged according to the following conditions

People participated in the contest:

(1) When a participates, B also participates;

(2) B and C only one person participates;

(3) C and D either participate, or neither;

(4) The participation of at least one person in D and E;

(5) If E participates, then both A and D also participate.

Input format:

No

Output format:

Uppercase letters indicate the person who participates, without spaces in the middle.

For example, the end result is that A and d participate, then the output

AD

Coding:

#include <stdio.h>int main () {int a,b,c,d,e;for (a=0; a<2; a++) for (b=0; b<2; b++) for          (c=0; c<2; C + +) for              (d=0; d<2; d++) for                  (e=0; e<2; e++)                  {                      if (A &&! B) continue;                      if ((B && C) | | (! B &&! C)) continue;                      if (C &&! D) | | (! C && D)) continue;                      if (! D &&! E) continue;                      if (E && (! A | | ! D)) continue;                      if (a==1) printf ("A"), if (b==1) printf ("B"), if (c==1) printf ("C"), if (d==1) printf ("D"), if (e==1) printf ("E");                  }    return 0;}

2, a criminal police brigade of 6 suspects involved in a case analysis: (10 points)

Topic content:

A criminal police brigade on the 6 suspects involved in an analysis of the mystery:
      ⑴a, b at least 1 people commit crimes;
        ⑵a, E, F, at least 2 of the 3 persons involved in the crime;
        
           ⑷b, C or at the same time, or are not related to the case;
           ⑸c, D and only one person committing the crime;
           ⑹ If D did not participate in the crime, then E could not participate in the crime.
Programming to find out who the perpetrator was.

Input format:

Output format:

Uppercase letters indicate the person who participates, without spaces in the middle.

For example, the end result is that A and d participate, then the output

AD

Coding:

#include <stdio.h> int main () {int A, B, C, D, E, F;//define A to e six variables, commit equal to 1, otherwise equal to 0 for (A = 0; A < 2; A + +) for (B = 0; B < 2; B + +) for (C = 0; C < 2; C + +) for (D = 0; D < 2; d++) for (E = 0; E < 2; e++) for (F = 0; F < 2; f++) {if (6 = = (A | | b)//a, b at least one person committed the crime + (!) ( A && D)//a, D cannot be accomplice + ((a && E) | | (A && F) | |   (E && F)) A, E, F Three have at least two people involved in the Crime + ((B && C) | | (! B &&! c)//b, C or at the same time, or unrelated to the case + (c &&! D) | | (D &&!) C)//c, D and only one person committed the crime + (d| | (!  e))//If D does not participate in the crime, then E is also unlikely to participate in the crime. {if (a==1) printf ("A"), if (b==1) printf ("B"), if (c==1) printf ("C"), if (d==1) printf ("D"), if (e==1) printf ("E");            F (f==1) printf ("F");  }} return 0;   }

　　

　　

　　

C Language: Logical reasoning