C language: returns the pointer to the first element of two arrays, and outputs this value, array pointer

C language: returns the pointer to the first element of two arrays, and outputs this value, array pointer

//

// Main. c

// Pointer_search

//

// Created by ma c on 15/8/2.

// Copyright (c) 2015 bjsxt. All rights reserved.

// Requirement: Compare the elements in two ordered arrays by searching the pointer and output the first identical element value in the two arrays.

 

# Include <stdio. h>

Int * searchSameElement (int * a, int * B, int len1, int len2 );

Int main (int argc, const char * argv [])

{

Int a [] = {4, 51, 8, 6, 7, 10 };

Int B [] = {80, 8, 10, 90, 7, 10, 51 };

Int len1 = sizeof (a)/sizeof (a [0]);

Int len2 = sizeof (B)/sizeof (B [0]);

Int * pt = searchSameElement (a, B, len1, len2); // returns the first address of the same value.

If (pt)

Printf ("% d \ n", * pt );

Else

Printf ("the same number don not find! \ N ");

Return 0;

}

Int * searchSameElement (int * a, int * B, int len1, int len2)

{

Int * pa =;

Int * pb = B;

While (pa ++) <(a + len1 ))

{

While (pb <(B + len2 ))

{

If (* pa! = * Pb)

{

Pb ++;

}

Else

{

Return pa;

}

}

}

Return 0;

}