C language to determine whether a number is a palindrome number

Note: palindrome number is the number along and reverse is the same number!

Read Haobin Teacher's C language video, although still only read more than 80, but still have some experience, programming should develop good programming style, at least so far write these small programs should have the following such a process:

1, process (know how the program is running in the same order)

2, function (understanding the role of the program)

3, test number (I personally understand the test process, as a computer to carry out the program)

/*

April 20, 2012 10:36:23

Judge whether a number is a palindrome number

*/

#include <stdio.h>

int main (void)

{

int Val; Storing data to be judged

int m;

int sum = 0;

printf ("Please enter the number you need to judge: \ n");

scanf ("%d", &val);

m = val;

/* This piece is the core code block:

From the number of input from the sum of 10, hundreds ... In order to get the inverse number, we need to *10 and add the next one as a single-digit

Sum is updated every time, the M value is removed and the last one is updated

*/

while (m)

{

sum = sum*10 + m%10;

M/= 10;

}

if (sum = = val)

printf ("yes!\n");

Else

printf ("no!\n");

return 0;

}

Trial process (pure physical activity)

/*

The process of judging whether it is a palindrome number

Just test the core block here.

*/

1234

1-> m = val = 1234; sum = 0 + 1234%10 = 4; m = 1234/10 = 123;

2-> m = 123; sum = 40 + 123%10 = 40+3 = 43; m = 123/10 = 12;

3-> m = 12; sum = 430 + 12%10 = 432; m = 12/10 = 1;

4-> m = 1; sum = 4320 + 1%10 = 4321; m = 1/10 = 0;

False

12321

1-> m = val = 12321; sum = 0 + 12321%10 = 1; m = 12321/10 = 1232;

2-> m = 1232; sum = 10 + 1232%10 = 12; m = 1232/10 = 123;

3-> m = 123; sum = 120 + 123%10 = 123; m = 123/10 = 12;

4-> m = 12; sum = 1230 + 12%10 = 1232; m = 12/10 = 1;

5-> m = 1; sum = 12320 + 1%10 = 12321; m = 1/10 = 0;

False

See more highlights of this column: http://www.bianceng.cnhttp://www.bianceng.cn/Programming/C/