C Language: Write a function print for the output list

Write a function printfor the output list.

Solution: Program:

#include <stdio.h>

#include <stdlib.h>

#define LEN sizeof (struct Student)

struct Student

{

Long num;

Float score;

struct Student *next;

};

int n;

struct Student *creat ()//function to create a linked list

{

struct Student *head;

struct Student *p1, *p2;

n = 0;

P1 = P2 = (struct Student *) malloc (LEN);

scanf ("%ld,%f", &p1->num, &p1->score);

head = NULL;

while (P1->num! = 0)

{

n = n + 1;

if (n = = 1)

{

head = p1;

}

Else

{

P2->next = p1;

}

P2 = p1;

P1 = (struct Student *) malloc (LEN);

scanf ("%ld,%f", &p1->num, &p1->score);

}

P2->next = NULL;

return (head);

}

void print (struct Student *head)//function of the output list

{

struct Student *p;

printf ("\nnow,these%d records are:\n", N);//records record

p = head;//p points to 1th node

if (head! = NULL)//Is not an empty table

{

Do

{

printf ("%ld%5.1f\n", P->num, P->score);

p = p->next;

} while (P! = NULL);

}

}

void Main ()

{

struct Student *head;

Head= creat ();//Call function returns the address of the 1th node of the list.

Print (head);

}

Results:

1001,77

1003,88

1005,99

0,0

Now,these 3 Records is:

1001 77.0

1003 88.0

1005 99.0

Please press any key to continue ...

This article is from the "Rock Owl" blog, please be sure to keep this source http://yaoyaolx.blog.51cto.com/10732111/1750277

C Language: Write a function print for the output list