Brief Introduction
Analog Bank of capital output for example
345
Three restaurants
Method/Step
First Open VC + +
File "" New
Create a C + + blank Document
Declare header file first
Copy Code code as follows:
declaring variables
Copy Code code as follows:
Char *p[10]={"0", "one", "two", "three", "four", "five", "six", "seven", "eight", "Nine"};
Because of the use of a custom function, we first declare
Copy Code code as follows:
void Printinterger (char a[], int len);/* Output Integer PART * *
void Printdecimal (char a[],int len)/* Output Decimal Part * *
Function 1, for outputting integer parts, mainly using switch case for matching conversions
Copy Code code as follows:
void Printinterger (char a[], int len)
{
int I, J, Tag1, Tag2, TAG3;
tag1= (a[len-6]== ' 0 ' && a[len-7]== ' 0 ' && a[len-8]== ' 0 ');
tag2= (a[len-14]== ' 0 ' && a[len-15]== ' 0 ' && a[len-16]== ' 0 ');
tag3= (a[len-22]== ' 0 ' && a[len-23]== ' 0 ' && a[len-24]== ' 0 ');
printf ("Your money is: \ n");
for (I=0,j=len; I<len && j>0; i++,j--)
{
if (a[i] = = ' 0 ' && i!= len-1)
{
if (j = = 5 && tag1) | | (j = && Tag2) | | (j = = && Tag3))
;
else if (j = &&! Tag3) | | (j = = 5 &&! Tag1) | | (j = && Tag2))
printf ("Million");
else if (j = = 9 | | j = = 17)
printf ("billion");
else if (a[i+1] = = ' 0 ' && i!= len-1)
;
else if (a[i+1]!= ' 0 ' && i!= len-1)
printf ("0");
Else
;
}
else if (a[i] = = ' 0 ' && i = = len-1)
;
else if (A[i]!= ' 0 ')
{
/* The conversion of Arabic numerals to Chinese characters * *
Switch (A[i])
{
Case ' 1 ': printf ("%s", p[1]); Break
Case ' 2 ': printf ("%s", p[2]); Break
Case ' 3 ': printf ("%s", p[3]); Break
Case ' 4 ': printf ("%s", p[4]); Break
Case ' 5 ': printf ("%s", p[5]); Break
Case ' 6 ': printf ("%s", p[6]); Break
Case ' 7 ': printf ("%s", p[7]); Break
Case ' 8 ': printf ("%s", p[8]); Break
Case ' 9 ': printf ("%s", p[9]); Break
default:printf ("error");; Break
}
/* Output corresponding unit * *
Switch (j)
{
Case 2:
Case 6:
Case 10:
Case 14:
Case 18:
Case 22:printf ("%s", "ten"); Break
Case 3:
Case 7:
Case 11:
Case 15:
Case 19:
Case 23:printf ("%s", "Hundred"); Break
Case 4:
Case 8:
Case 12:
Case 16:
Case 20:
Case 24:printf ("%s", "thousand"); Break
Case 5:
Case 13:
Case 21:printf ("%s", "million"); Break
Case 9:
Case 17:printf ("%s", "billion"); Break
default:printf ("%s", ""); Break
}
}
}
printf ("%s", "Round");
}
Function 2, for outputting decimal parts, mainly using switch case for matching conversion
Copy Code code as follows:
void Printdecimal (char a[],int len)
{
int i;
for (i=0; i<len; i++)
{
/* The conversion of Arabic numerals to Chinese characters * *
Switch (A[i])
{
Case ' 0 ': printf ("%s", p[0]); Break
Case ' 1 ': printf ("%s", p[1]); Break
Case ' 2 ': printf ("%s", p[2]); Break
Case ' 3 ': printf ("%s", p[3]); Break
Case ' 4 ': printf ("%s", p[4]); Break
Case ' 5 ': printf ("%s", p[5]); Break
Case ' 6 ': printf ("%s", p[6]); Break
Case ' 7 ': printf ("%s", p[7]); Break
Case ' 8 ': printf ("%s", p[8]); Break
Case ' 9 ': printf ("%s", p[9]); Break
default:printf ("%s", p[0]);; Break
}
/* Output corresponding unit * *
Switch (i)
{
Case 0:printf ("%s", "angle"); Break
Case 1:printf ("%s", "Min"); Break
Case 2:printf ("%s", "pct"); Break
Case 3:printf ("%s", "Hao"); Break
Default:; Break
}
}
}
The main function, the function of the variable I explained
Copy Code code as follows:
int main (void)
{
Char number[128];/* is used to hold the number entered by the user.
Char interger[64], decimal[64];/* an integer and a decimal part that holds the input number respectively.
int leni,lend;/* records the length of integers and decimal parts separately.
int i,j;
Puts ("*************************************");
Puts ("* This are a print program *");
Puts ("* used in a bank *");
Puts ("*************************************");
Puts ("Please input the money:");
Gets (number);
i=0;j=0;
/* Process the integer part of the number entered.
while ((number[i]!= '/0 ') && (number[i]!= '. ') && (number[i] >= ' 0 ') && (Number[i] <= ' 9 '))
{
Interger[i]=number[i];
i++;
}
LenI = i;
if (number[i]== '. ')
{
i++;
/* Processing the number of inputs of the decimal part of the * * *
while (number[i]!= '/0 ' && number[i] >= ' 0 ' && number[i] <= ' 9 ')
{
Decimal[j++]=number[i++];
}
/* Accurate to 4 digits after the decimal point * *
if ((J >= 4) && (Decimal[4] > ' 5 '))
{
decimal[3]+=1;/* carry out 4 homes five into operation * *
DECIMAL[4] = '/0 ';
}
}
if (J >= 4)
LenD = 4;
Else
LenD = j;
Printinterger (Interger, LenI);
Printdecimal (Decimal,lend);
printf ("\ n");
return 0;
}
Run results
